Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.
Answer:
A
![N = 1340.86 \ slits / cm](https://tex.z-dn.net/?f=N%20%20%3D%201340.86%20%5C%20slits%20%20%2F%20cm)
B
![\theta = 15.7^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%2015.7%5Eo)
Explanation:
From the question we are told that
The wavelength is
The angle of first bright fringe is
The order of the fringe considered is n =1
Generally the condition for constructive interference is
=> ![d = \frac{1 * 650 *10^{-9 }}{ sin(5)}](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cfrac%7B1%20%2A%20%20650%20%2A10%5E%7B-9%20%7D%7D%7B%20sin%285%29%7D)
=> ![d = 7.458 *10^{-6} \ m](https://tex.z-dn.net/?f=d%20%3D%207.458%20%2A10%5E%7B-6%7D%20%5C%20%20m)
Converting to cm
![d = 7.458 *10^{-6} \ m = 7.458 *10^{-6} * 100 = 0.0007458 \ cm](https://tex.z-dn.net/?f=d%20%3D%207.458%20%2A10%5E%7B-6%7D%20%5C%20%20m%20%3D%207.458%20%2A10%5E%7B-6%7D%20%20%2A%20100%20%3D%20%200.0007458%20%5C%20%20cm)
Generally the number of grating pre centimeter is mathematically represented as
![N = \frac{1}{d}](https://tex.z-dn.net/?f=N%20%20%3D%20%20%5Cfrac%7B1%7D%7Bd%7D)
=> ![N = \frac{1}{0.0007458}](https://tex.z-dn.net/?f=N%20%20%3D%20%20%5Cfrac%7B1%7D%7B0.0007458%7D)
=> ![N = 1340.86 \ slits / cm](https://tex.z-dn.net/?f=N%20%20%3D%201340.86%20%5C%20slits%20%20%2F%20cm)
Considering question B
From the question we are told that
The first wavelength is
The second wavelength is
The order of the fringe is ![n = 2](https://tex.z-dn.net/?f=n%20%20%3D%20%202)
The grating is ![N = 5000 \ slits / cm](https://tex.z-dn.net/?f=N%20%3D%20%205000%20%5C%20%20slits%20%2F%20cm)
Generally the slit width is mathematically represented as
![d = \frac{1}{N }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cfrac%7B1%7D%7BN%20%20%7D)
=> ![d = \frac{1}{ 5000 }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cfrac%7B1%7D%7B%205000%20%20%7D)
=> ![d = 0.0002 \ c m = 2.0 *10^{-6} \ m](https://tex.z-dn.net/?f=d%20%3D%20%20%200.0002%20%5C%20%20c%20m%20%20%3D%20%202.0%20%2A10%5E%7B-6%7D%20%5C%20m)
Generally the condition for constructive interference for the first ray is mathematically represented as
=>
=> ![\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20650%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> ![\theta_1 = 40.5 ^o](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%2040.5%20%5Eo)
Generally the condition for constructive interference for the second ray is mathematically represented as
=>
=> ![\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20420%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> ![\theta_2 = 24.8 ^o](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%2024.8%20%20%5Eo)
Generally the angular separation is mathematically represented as
![\theta = \theta_1 - \theta_1](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20%5Ctheta_1%20-%20%5Ctheta_1)
=> ![\theta = 42.5^o - 24.8^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%2042.5%5Eo%20-%20%2024.8%5Eo)
=> ![\theta = 15.7^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%2015.7%5Eo)
Increase because the mass of an object aligns with its weight
Answer:
It is likely to be option B: 50 degrees and 50 degrees
Hope it helps.......... pls mark as brainliest.