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2 years ago

9

(17)) During adiabatic compression

1 answer:

Snowcat [4.5K]2 years ago

7 0

Answer:

a.remains constant

Explanation:

<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em> </em><em>y</em><em>o</em><em>u</em><em>.</em>

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2 years ago

Read 2 more answers

On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.0∘F∘F to 45.0∘F∘F in just 2 minutes. What was the

Margaret [11]

Answer:

The change in temperature, $\Delta T=9.45^{\circ} C$

Explanation:

Given that,

The temperature in Spearfish, South Dakota, rose from $-4^{\circ} F\ to\ 45^{\circ} F$ in just 2 minutes. We need to find the temperature change in Celsius degrees. Change in temperature is given by final temperature minus initial temperature such that,

$\Delta T=T_f-T_i\\\\\Delta T=45-(-4)\\\\\Delta T=49^{\circ}F$

The relation between degrees Celsius and degrees Fahrenheit is given by :

$F=1.8C+32$

Here, F = 49 degrees

$49=1.8C+32\\\\\Delta T=9.45^{\circ} C$

So, the change in temperature is 9.45 degree Celsius. Hence, this is the required solution.

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3 years ago

A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p

olya-2409 [2.1K]

Answer:

Acceleration of proton will be $a=0.67\times 10^{11}m/sec^2$

Explanation:

We have given a proton is placed in an electric field of intensity of 700 N/C

So electric field E = 700 N/C

Mass of proton $m=1.67\times 10^{-27}kg$

Charge on proton $e=1.6\times 10^{-19}C$

So electric force on the proton $F=qE=1.6\times 10^{-19}\times 700=1.120\times 10^{-16}N$

This force will be equal to force due to acceleration of the proton

According to newton's law force is given by F = ma

So $1.67\times 10^{-27}\times a=1.120\times 10^{-16}$

$a=0.67\times 10^{11}m/sec^2$

So acceleration of proton will be $a=0.67\times 10^{11}m/sec^2$

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