3 years ago

(17)) During adiabatic compression

Physics

1 answer:

Snowcat [4.5K]3 years ago

7 0

Answer:

a.remains constant

Explanation:

Hope this help you.

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Answer:

∈= $3.1584x10^{26} \frac{V}{m}$

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈ $=\frac{P}{E_{o}}$

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$P=\frac{q}{V}$

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4 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

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First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
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the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
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Ans the answer is 0.25J

Explanation

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PE = mgz = 200 * 9.81 *1000 = 1962 KJ

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