Answer:
456.4 N
Explanation:
From conservation of energy, the potential energy is converted to kinetic energy hence
mgh=½mv²
Making v the subject then
Where g is acceleration due to gravity and h is height whike v is final velocity. Substituting 4.9m for h and 9.81 m/s² for g then
Change in momentum equals to the impulse.
Impulse, I= Ft
Change in momentum, ∆p= m(v-u)
Ft=m(v-u) making F the subject of formula then
Where F is force in Newton, t is time in seconds, m is mass of diver, v and u are the final and initial velocities respectively.
Substituting 68 kg for m, 9.8 m/s for v, 0 m/s for u since it is initially at rest and 1.46 s for t
Answer:
It's due to the distance from either ends of strings origin...
Explanation:
As we know that waves behave moving in a flow from one side to another side and this gives a prospective of motion. Suppose a wave is pinched from the near one end of a guitar then due to the distortion created by the point of tie of strings the wave super imposes and moves with a velocity v and produces a wave frequency f. as we the pinching go down to the center the wave stabilizes itself to a stationary origin right at the center and the frequency then changes accordingly as moving down on the string.
Answer:
a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s
Explanation:
a) This is a kinematics exercise, let's write the equation of each vehicle
car
x = x₀ + v₀ t + ½ a t²
Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0
x₀ = v₀ = 0
we substitute
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
at the point where they are, their positions are equal
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.70
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 2.70 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.70 11.407
v = 30.80 m / s
