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taurus [48]
3 years ago
12

A wagon weighs 1,800 N and is pulled by a horse at a speed of 0.40 meters/ second. What is the power of this horse

Physics
2 answers:
Nataly [62]3 years ago
5 0

Answer:

2w

Explanation:

I just did the assignment and i got it right so trust me. Also please give me a *thanks*

Alona [7]3 years ago
4 0

Answer:

Power=720[watt]

Explanation:

We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.

In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.

Power= W/T\\T=time [s]\\W=work [J]\\Power = F*V\\where\\V=velocity [m/s]\\Power=1800 * 0.4 = 720 [watt]

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Which of the following statements are true? Select all that apply.
beks73 [17]

Answer:

The following options are true based on the properties of electric field;

a) Electric field lines near positive point charges radiate outward.

b) The electric force acting on a point charge is proportional to the magnitude of the point charge.

d) In a uniform electric field, the field lines are straight, parallel, and uniformly spaced.

Explanation:

From option b) From coulomb's law F = Kq1q2r/r2

5 0
4 years ago
The force of gravity on the moon is only 16.6% the force of gravity on Earth. For each item listed in the table below, fill in w
Dmitry [639]

==> Take an Earth weight. Don't forget the unit.

==> Multiply it by 0.166 .

==> The product is its Moon weight. Don't forget the unit.

Example:

If I weigh 1,000 lbs on Earth.

Multiply 1,000 lbs by 0.166 .

I weigh 166 lbs on the Moon

4 0
3 years ago
If do 50 J of Work in 20 seconds, what is my Power ?
pochemuha

Answer: P= W/t so P=50/20 =2.5 W

8 0
3 years ago
One star has a temperature of 30,000 K and another star has a temperature of 6,000 K. Compared to the cooler star, how much more
Lilit [14]

Answer:

<em>The hotter star radiates 625 times more energy per second from each square meter of its surface</em>

<em></em>

<em></em>

Explanation:

Temperature of the hotter star is 30000 K

temperature of the cooler star = 6000 K

From Stefan-Boltzmann radiation laws, for a non black body

P = εσAT^{4}

where

P is the energy per second or power of radiation

ε is the emissivity of the body

σ is the Stefan-Boltzmann constant of proportionality

A is the area of the sun

T is the temperature of the sun

The sun can be approximated as a black body, and the equation reduces to

P = σAT^{4}

For the hotter body,

P = σA(30000^{4}) = 8.1 x 10^17σA  J/s

For the cooler body,

P = σA(6000^{4}) = 1.296 x 10^15σA   J/s

comparing the two stars energy

==> (8.1 x 10^17)/(1.296 x 10^15) = 625

<em>This means that the hotter star radiates 625 times more energy per second from each square meter of its surface</em>

<em></em>

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3 years ago
Precautions taken when doing experiment on simple pendulum​
olchik [2.2K]

Answer:

1.)The bob of pendulum should be displaced with a small angle.

2) The amplitude of the oscillation of a simple pendulum should be small.

3) Fans should be switched off to reduce the air resistance.

4)The simple pendulum should be oscillate in a vertical plane

Hope this helped you

7 0
4 years ago
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