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Xelga [282]
3 years ago
12

Determine the 3 standing waves for a 4 m length of rope.

Physics
1 answer:
strojnjashka [21]3 years ago
7 0

Harmonics, Loop and Harmonic number

Hope this helps :)

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Give reason : the action and reaction do not lead to equilibrium ?
Natalija [7]

the action and reaction do not lead equilibrium if action and reaction force react on different objects

4 0
3 years ago
An igneous intrusion whose boundaries lie parallel to the layering in the surrounding country rock is considered to be:
ikadub [295]
<span>...a concordant intrusion. In geology, "concordant" means the same as "sill" -- or, an intrusion that has gotten in between older layers of rock (or even beds of volcanic lava). An intrusion with boundaries parallel to layering in surrounding rocks suggests this, meaning it is considered to be a concordant intrusion.</span>
7 0
3 years ago
Light of wavelength 597 nm falls on a double slit, and the first bright fringe of the interference pattern is seen at an angle o
Kazeer [188]

Answer:

2.2 µm

Explanation:

For constructive interference, the expression is:

d\times sin\theta=m\times \lambda

Where, m = 1, 2, .....

d is the distance between the slits.

Given wavelength = 597 nm

Angle, \theta  = 15.8°

First bright fringe means , m = 1

So,

d\times sin\ 15.8^0=1\times \597\ nm

d\times 0.2723=1\times \597\ nm

d=2192.43481\ nm

Also,

1 nm = 10⁻⁹ m

1 µm = 10⁻⁶ m

So,

1 nm = 10⁻³ nm

Thus,

<u>Distance between slits ≅ 2.2 µm</u>

8 0
3 years ago
Read 2 more answers
Evan drew a diagram to illustrate radiation.
Vesna [10]

The correct answer is:

D. Electromagnetic waves.

The arrows represent electromagnetic waves.

|Huntrw6|

8 0
3 years ago
Calculate the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m
otez555 [7]

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

T = 2 \pi \sqrt\frac{m}{k}

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

5 0
3 years ago
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