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Xelga [282]
3 years ago
12

Determine the 3 standing waves for a 4 m length of rope.

Physics
1 answer:
strojnjashka [21]3 years ago
7 0

Harmonics, Loop and Harmonic number

Hope this helps :)

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Which of the following describes an action-reaction pair?
Diano4ka-milaya [45]
Answer B is the correct pair.
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3 years ago
Describe the orbit in which planets revole around the sun
Novay_Z [31]
Planets orbit the sun in the paths which are known as elliptical orbit. Each planet has its own orbit around the sun and direction in which all the planets orbit around the sun are the same. These orbits were well explained by the astronomer Kepler. The gravity of the Sun keeps the planets in their orbits. They stay in their orbits because there is no other force in the Solar System which can stop them.
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1 year ago
13. A proton moves at 7.50×107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path o
diamong [38]

The magnetic force acting on a charged particle moving perpendicular to the field is:

F_{b} = qvB

F_{b} is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.

The centripetal force acting on a particle moving in a circular path is:

F_{c} = mv²/r

F_{c} is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.

If the magnetic force is acting as the centripetal force, set F_{b} equal to F_{c} and solve for B:

qvB = mv²/r

B = mv/(qr)

Given values:

m = 1.67×10⁻²⁷kg (proton mass)

v = 7.50×10⁷m/s

q = 1.60×10⁻¹⁹C (proton charge)

r = 0.800m

Plug these values in and solve for B:

B = (1.67×10⁻²⁷)(7.50×10⁷)/(1.60×10⁻¹⁹×0.800)

B = 0.979T

5 0
3 years ago
a particle with a charge of 5.5 x 10^-8 c is 3.5 cm from a particle with a charge of -2.3 x10^-8 c. the potential energy of this
Yuri [45]

Answer:

-32.5 * 10^-5 J

Explanation:

The potential energy of this system of charges is;

Ue = kq1q2/r

Where;

k is the Coulumb's constant

q1 and q2 are the magnitudes of the charges

r is the distance of separation between the charges

Substituting values;

Ue = 9.0×10^9 N⋅m2/C2 * 5.5 x 10^-8 C *( -2.3 x10^-8) C/(3.5 * 10^-2)

Ue= -32.5 * 10^-5 J

4 0
3 years ago
The power rating of an electric lawn mower is 2000 watts if lawnmower is used for 120 seconds how many joules of work van it do
Scorpion4ik [409]
1 watt = 1 joule/sec

2,000 watts = 2,000 joules/sec

                     (2,000 joule/sec) x (120 sec)

                  = (2,000 x 120)  (joule-sec/sec)

                  =   240,000 joules .
        
4 0
2 years ago
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