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yan [13]
3 years ago
8

I will give 14 points & make you the brainiest

Physics
1 answer:
Virty [35]3 years ago
8 0

Answer:

B. silicate rocks and metals

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A student recorded the favorite dipping sauces of the 70 people in his class. He wants to plot these data in a circle graph:
daser333 [38]

Explanation:

There are 70 people in a class. A student wants to plot these data in a circle.  

We need to find the angle should the wedge for barbecue have.

There are 20 such students that like barbecue.

So,

B=\dfrac{20}{70}\times 360^{\circ}\\\\B=102.85^{\circ}

or

B = 103°

It means that 103° on the circle shows the number of students that like barbecue .

5 0
3 years ago
An airplane travels in a straight line directly from Washington, D.C., to Atlanta, Georgia. Ignoring take off and landing, what
saw5 [17]
<h3>Correct answer choice is:</h3><h2>Velocity.</h2><h3>Explanation:</h3>

The velocity remains constant throughout the journey because the airplane can not reduce its velocity to maintain the balance in the air and to keep on moving.

In terms of plane cruising, the two central forces changing its velocity ahead are pull and thrust. At a fixed height, when the force of thrust equals the opposite force of resistance, then the plane will undergo consistent movement in one direction. This can be additionally defined by Newton's First Law.

8 0
3 years ago
Read 2 more answers
3. A 0.35 kg puck slides across the ice with an average force of friction of 0.15 N acting on it. It slides 82 m before coming t
sattari [20]

Answer:

Work done is 12.3 J

Explanation:

We have,

Mass of puck, m = 0.35 kg

Force of friction acting on the puck when it slides is 0.15 N

Distance travelled by the puck is 82 m.

It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by

W=Fd\\\\W=0.15\times 82\\\\W=12.3\ J

The work done on the puck is 12.3 J.

5 0
4 years ago
In Part l, the independent variable was
Ber [7]

Answer:

The independent variable is the variable the experimenter manipulates or changes, and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

7 0
3 years ago
A long, thin solenoid has 390 turns per meter and a radius of 1.20 cm. The current in the solenoid is increasing at a uniform ra
gtnhenbr [62]

To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.

By definition the induced electromotive force is defined as

\int E dl = -\frac{d\phi}{dt}

\int E dl = -(\frac{dB}{dt})A

Where,

\phi = Electric field

B = Magnetic Field

A = Area

At the theory the magnetic field is defined as,

B = \mu_0 NI

Where,

N = Number of loops

I = current

\mu_0 = Permeability constant

We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then

A = \pi r^2

l = 2\pi r

Replacing at the previous equation we have that

E (2\pi r) = \mu_0 n (\frac{di}{dt})(\pi R^2)

Where,

R = Radius of the solenoid

r = The distance from the axis

Re-arrange to find the current in function of time,

\frac{di}{dt} = \frac{Er}{\mu_0 NR^2}

Replacing our values we have

\frac{di}{dt} = \frac{(8.00*10^{-6})(0.0348)}{(4\pi*10^{-7})(390)(1.2*10^-2)^2}

\frac{di}{dt} = 3.94487A/s

8 0
3 years ago
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