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alexgriva [62]
4 years ago
8

What is a harmful role of bacteria?

Chemistry
1 answer:
zzz [600]4 years ago
6 0

Answer:

sickness.

Explanation:

some bacterium cause sickness, kike a stomach bug.

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Gimme the sandmeyer's reaction!!!​
iren2701 [21]

Answer:

The Sandmeyer reaction is a chemical reaction used to synthesize aryl halides from aryl diazonium salts using copper salts as reagents or catalysts. It is an example of a radical-nucleophilic aromatic substitution.

4 0
3 years ago
Chemical name for Fe2O3?
Flura [38]
The chemical name is ferric oxide or  iron (III) oxide or hematite. We can found it naturaly as a magnetite, mineral.
4 0
4 years ago
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In water, naoh almost completely separates into na+ and oh- ions. thus, naoh is _____.​
stepan [7]
<span>In water, naoh almost completely separates into na+ and oh- ions. thus, naoh is Stong base.
Strong bases and strong acids completely ionized in the water,So when NaOH is added into water, it is completely ionized and forms Na+ and OH- ions and it shows that it is a strong base.</span>
3 0
4 years ago
Which of the following represent impossible combinations of n and I? (a) 1p, (b) 4s, (c) 5f, (d) 2d 6.61
Eduardwww [97]

Answer:

  • <u>Options (a) and (d) : (a) 1p and (d) 2d represent impossible combinations of n and l.</u>

Explanation:

n refers to the principal quantum number, and l refers to the angular momentum or Azimuthal quantum number.

Principal quantum number (n) is used to indicate the main energy level of the electron. It may take whole numbers: 1, 2, 3, 4, 5, 6, 7, ...

Angular momentum or Azimuthal quantum number refers to the kind (shape) of the orbital. It can take numbers from 0 to n - 1.

So, if n = 1, l can only be 0; if n = 2, l can be either 0 or 1; if n = 2, l can be either 0, 1 or 2.

On the other hand, the shape of the orbitals is also representd by a letter. then there is a unique relation between the letter that represents the orbital and the angular quantum number which is:

letter       l number

s               0

p               1

d               2

f                3

The previous information is summarized in the next table:

n    possible l numbers          

1          0                                          

2         0, 1                                        

3         0, 1, 2                                    

4         0, 1, 2, 3                              

5        0, 1, 2, 3, 4

6        0, 1, 2, 3, 4, 5

7        0, 1, 2, 3, 4, 5, 6

As per the choices given in the question you have:

<u>(a) 1 p</u> is not possible because when n = 1 the only l number is 0 and it is an s orbital, but p ⇒ l = 1. Thus, this is a correct choice.

<u>(b) 4s</u> is possible since n = 4 permits l to be 0, 1, 2, and 3.

<u>(c) 5f </u>is possible since n = 5 permits l to be 0, 1, 2, 3, and 4.

<u>(d) 2d</u> is impossible since n = 2 permits l to be 0, and 1, but d ⇒ l = 2. Thus, this is other right choice.

4 0
3 years ago
Calculate the Ka of a 0.35M weak acid with a pH of 4.2.
Nadusha1986 [10]

Answer:

Ka = 1.14x10⁻⁸

Explanation:

First we <u>calculate [H⁺] from the pH</u>:

  • pH = -log[H⁺]
  • [H⁺] = 10^{-pH}
  • [H⁺] = 6.31x10⁻⁵ M

For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:

  • [H⁺] = √(C*Ka)

Where C is the molar concentration of the weak acid solution.

  • 6.31x10⁻⁵ M = \sqrt{0.35M*Ka}
  • 1.14x10⁻⁸ = Ka
8 0
3 years ago
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