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2 years ago

Find the slope of a line that passes through points (–1, –5) and (6, 9). Question 2 options: A) 1∕2 B) –2 C) 4∕5 D) 2

Mathematics

1 answer:

hichkok12 [17]2 years ago

4 0

Answer:

$D) 2$

Step-by-step explanation:

The slope of a line is used to describe the average rate of change. Often referred to as the ( $\frac{rise}{run}$ ), the general formula to find the slope of a line is the following,

$\frac{y_2-y_1}{x_2-x_1}$

Where ( $x_1,y_1$ ) and ( $x_2,y_2$ ) are both points on the line. One is given that the following points are on the line,

$(-1, -5)\\\\(6, 9)$

Substitutes these values into the formula and solve for the slope,

$\frac{9-(-5)}{6-(-1)}$

Simplify, remember negative times negative equals positive,

$\frac{9+5}{6+1}$

Combine like terms,

$\frac{14}{7}$

Simplify further, remember a fraction is another way of representing division,

$2$

You might be interested in

The sum of the ages of three brothers Tema,Juma and Abdul is 65 years. Juma is twice as old as Abdul and a half times as old as

Ber [7]

Answer:

Tema = 26 years

Juma = 13 years

Abdul = 26 years

Step-by-step explanation:

Let their ages be represented as:

Tema = x

Juma = y

Abdul = z

From the question, we are told that:

Juma is twice as old as Abdul

y = 2z

z = y/2

= 0.5y

And Juma is a half times as old as Tema.

y = 1/2x

y = 0.5x

x = y/0.5

x = 2y

Hence,

x + y + z = 65

2y + y + 2y = 65

= 5y = 65

y = 65/5

y = 13 years

Since y = Zuma's age, Zuma is 13 years old

From the above question

Since 2y = z

y = 13

2 × 13 = z

z = 26

Since z = Abdul's age, Abdul is 26 years old

From the above question

x = 2y

y = 13 years

x = 2 × 13 years

x = 26 years.

Since x = Tema's age

Tema is 26 years.

Therefore, their present ages are:

Tema = 26 years

Juma = 13 years

Abdul = 26 years

7 0

2 years ago

Find angle <QPS in the diagram

marin [14]

Answer:

40°

Step-by-step explanation:

Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.

4 0

2 years ago

A company wants to find out if the average response time to a request differs across its two servers. Say µ1 is the true mean/ex

lorasvet [3.4K]

Answer:

a) The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

Test statistic t=0.88

The P-value is obtained from a t-table, taking into acount the degrees of freedom (419) and the type of test (two-tailed).

b) A P-value close to 1 means that a sample result have a high probability to be obtained due to chance, given that the null hypothesis is true. It means that there is little evidence in favor of the alternative hypothesis.

c) The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

d) The consequences of the confidence interval containing 0 means that the hypothesis that there is no difference between the response time (d=0) is not a unprobable value for the true difference.

This relate to the previous conclusion as there is not enough evidence to support that there is significant difference between the response time, as the hypothesis that there is no difference is not an unusual value for the true difference.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that there is significant difference in the time response for the two servers.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

$M_d=M_1-M_2=12.5-12.2=0.3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{3^2}{196}+\dfrac{4^2}{225}}\\\\\\s_{M_d}=\sqrt{0.046+0.071}=\sqrt{0.117}=0.342$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.3-0}{0.342}=\dfrac{0.3}{0.342}=0.88$

The degrees of freedom for this test are:

$df=n_1+n_2-1=196+225-2=419$

This test is a two-tailed test, with 419 degrees of freedom and t=0.88, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>0.88)=0.381$

As the P-value (0.381) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is significant difference in the time response for the two servers.

<u>Confidence interval </u>

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

The estimated standard error of the difference is s_Md=0.342.

The critical t-value for a 95% confidence interval and 419 degrees of freedom is t=1.966.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=1.966 \cdot 0.342=0.672$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 0.3-0.672=-0.372\\\\UL=M_d+t \cdot s_{M_d} = 0.3+0.672=0.972$

The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

7 0

3 years ago

Robin Inc. feared that the average company loss is running beyond $34,000. It initially conducted a hypothesis test on a sample

kipiarov [429]

Answer

b. Type II error

Step-by-step explanation:

The hypothesis was formulated as

the solution can be seen in the attached document

8 0

3 years ago

a diver is exploring the water of the great barrier reef she is currently 25 feet from the surface of the water and plans to exp

11111nata11111 [884]

Answer:

6.25

Step-by-step explanation:

she is at 25

she needs to be at 75 which means she needs 50 more feet

at 8 per minute she will reach the depth in 50/8 = 6.25 minutes or 6 minutes and 15 seconds

6 0

2 years ago