Answer: 10
Step-by-step explanation:
tony is 5 years younger than Marvin's age 1 year from now.
t = (m+1) - 5
t = m - 4
6 years ago tony was half as old as marvin was then.
t - 6 = 1/2(m - 6)
Get rid of the fraction, multiply both sides by 2
2(t-6) = m - 6
2t - 12 = m - 6
2t = m - 6 + 12
2t = m + 6
from the first statement, replace t with (m-4)
2(m-4) = m + 6
2m - 8 = m + 6
2m - m = 6 + 8
m = 14 is Marvin's present age
:
how old is tony now?
t = 14 - 4
t = 10 yrs is tony's age
I believe it would be the first option.
Answer:
The solution is x = e⁶
Step-by-step explanation:
Hi there!
First, let´s write the equation
ln(x⁶) = 36
Apply logarithm property: ln(xᵃ) = a ln(x)
6 ln(x) = 36
Divide both sides of the equation by 6
ln(x) = 6
Apply e to both sides
e^(ln(x)) = e⁶
x = e⁶
The solution is x = e⁶
Let´s prove why e^(ln(x)) = x
Let´s consider this function:
y = e^(ln(x))
Apply ln to both sides of the equation
ln(y) = ln(e^(ln(x)))
Apply logarithm property: ln(xᵃ) = a ln(x)
ln(y) = ln(x) · ln(e) (ln(e) = 1)
ln(y) = ln(x)
Apply logarithm equality rule: if ln(a) = ln(b) then, a = b
y = x
Since y = e^(ln(x)), then x =e^(ln(x))
Have a nice day!
There are 30 days in June and only three of those days are multiples of 8 so you have the probability of 3 out of 30.
Answer: 
Step-by-step explanation:
The confidence interval estimate for the population mean is given by :-
, where 
is the sample mean and ME is the margin of error.
Given : Sample mean: 
The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : 
Now, the confidence interval estimate for the population mean will be :-
Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =
