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Bumek [7]
3 years ago
14

A batch of 50 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi

lity that both parts are defective?
Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

we know that

P(both parts defective) = P(1st is defective) * P(2nd is defective)  

Probability of 1st detective:

total parts =50

number of defects =6

so,

P(1st is defective)

=\frac{6}{50}

Probability of 2nd detective:

total parts =49

number of defects =5

so,

P(2nd is defective)

=\frac{5}{49}

Probability of both detective:

P(both parts defective) is

=\frac{6}{50} *\frac{5}{49}

=\frac{3}{245}...............Answer

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Answer:

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Step-by-step explanation:

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t=\frac{-48}{-16},t=\frac{10}{-16}

t=3,t=-\frac{5}{8}

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