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Vladimir [108]
3 years ago
13

How do you find the angle of a triangle

Mathematics
2 answers:
Levart [38]3 years ago
4 0
Calculate the unknown angle. the sum of the internal angles equals 180 degrees

marissa [1.9K]3 years ago
4 0
Take both of your angles, add them up, then subtract the sum of that to 180 (40+50=90)(180-90=90) your result will be the missing angle of your triangle
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PLS HELP QUICK<br> Write an<br> equivalent expression (simplify): 14h + 12 - 8h - 3
aivan3 [116]

Answer:

22h - 9

Step-by-step explanation:

14h + 12 - 8h - 3

14h + 8h + 12 - 3

22h + 12 - 3

22h + 9

7 0
3 years ago
Please help. Find the two missing sides and write your answer as in simplified radical form.
ki77a [65]

Answer:

x and y =   5√2.

Step-by-step explanation:

This is a 45:45:90 triangle so length of x = length of y.

In this triangle the ratio of the sides is 1:1:√2

Finding length of x and y:

1/√2 = x/10

√2x = 10

x = 10/√2

=  10√2/2

=  5√2.

5 0
3 years ago
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
3 years ago
Plz help 10 mins left!!!!!!
mr_godi [17]
I think the ans is 5
3 0
3 years ago
Differentiate f(x) = \frac{x^{3}-4 x+1}{x^{3}}.
miv72 [106K]
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3 years ago
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