The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of 0.5 min
1 answer:
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Answer:
Relevant domain: [0 40]
Relevant range: [0 80]
Step-by-step explanation:
We have the following function:
In which C(t) is the water temperature.
t is the time.
The colling period ends when the water freezes (0°).
So it freezes after t minutes, and t is found when C(t) = 0. So
Relevant domain:
Input value of the function, which is in minutes. So between 0(initial) and 40(when the water freezes).
Relevant range:
Initial temperature, which is C(0) = 80, until it freezes, 0. So from 0 to 80.
Answer:
$59
Step-by-step explanation:
Let the revenue will be maximum when $ x is increased in the ticket price.
So, the final ticket price is $(18 + x) and attendance in the concert will be (500 - 5x)
So, revenue R = (18 + x) (500 - 5x) = 9000 + 410x - 5x².......... (1)
Condition for R to be maximum is
So, differentiating equation (1) with respect to x on both sides
⇒ x = 41
So, the ticket price for maximum revenue is $(18 + 41) = $59 (Answer)