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Lostsunrise [7]
3 years ago
10

Write the base number for each expression: Please I need with steps

Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

1) Base - 5

2) Base - 1.2

3) Base - \frac{1}{3}

Step-by-step explanation:

To find : Write the base number for each expression ?

Solution :

Base number is defined as the number written in exponent form a^n

which tells you to multiply a by itself, so a is the base of power n.

1) 5^{12}

In number 5^{12} the base is 5 as the power is 12.

2) 1.2^{2}

In number 1.2^{2} the base is 1.2 as the power is 2.

3) (\frac{1}{3})^{2}

In number  (\frac{1}{3})^{2} the base is \frac{1}{3} as the power is 4.

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When completely factored, 2x3 - 200x<br> equals-
telo118 [61]

Answer:

Step-by-step explanation:

The only way this can be factored is by pulling out the GCF. 2 and x are common to both terms:

2x(x^2-100)

BUT you should also recognize that what's inside the parenthesis is the difference of perfect squares. And that factors to

(x - 10)(x + 10). So the complete factorization is

2x(x - 10)(x + 10)

7 0
3 years ago
5. You answered 21 out of 25 questions correctly on a test. Did you reach your goal of getting at least 80%?
hichkok12 [17]

Answer:

You scored more than 80 %

Step-by-step explanation:

21/25  

We need to change this to a decimal, then to a percent

21/25 *4/4 = 84/100

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84>80.

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4 years ago
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It’s due late tonight can some pls help me pass
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Step-by-step explanation:

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3 0
3 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
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Find the measures of angles z, 1250<br>​
Y_Kistochka [10]

------------------------------

4 0
3 years ago
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