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Slav-nsk [51]
3 years ago
6

Find the common factor 12a^2b+24ab^2​

Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

(i) 2x = 2 × x. 3x2 = 3 × x × x. 4 = 2 × 2. The common factor is 1. (ii) 6abc = 2 × 3 × a × b × c. 24ab2 = 2 × 2 × 2 × 3 × a × b ...

Step-by-step explanation:

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PLEASE HELP ME ON MY FIRST QUESTION!, SHOW WORK PLEASE!!
kvasek [131]

Answer:

Solution given:

radius [r]=2cm

height [h]=8cm

total surface area of cylinder=?

we have

total surface area of cylinder=2πr²+2πrh

  • 2πr(r+h)
  • 2π*2(2+8)
  • 40π or 125.66cm²

<u>total surface area of cylinder</u><u>40π or 125.66cm²</u><u>.</u>

3 0
3 years ago
Read 2 more answers
Given the quadratic function
hjlf

The vertex is (-4,-3)

The axis of symmetry is x=-4

and the transformations are:

5 0
3 years ago
Drag and drop the steps to show the process for finding the inverse of the function below.
lilavasa [31]

Answer

h^-1(x)= x+43

Explanation

h(x)=x-43

Use substitution

y=x-43

Interchange the variables

x=y-43

Swap the sides

y-43=x

Move the constant to the right

y=x+43

Use substitution

h^-1(x)=x+43

4 0
2 years ago
What is the midpoint of EC ?
sergij07 [2.7K]

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

7 0
3 years ago
An empty cylindrical vase with a radius of 8 cm and a height of 9 cm is filled with 6 cm^3 of sand every 15 seconds. At the same
Andru [333]

General Idea:

The volume of cylinder is given by \pi r^{2} h, where r is the radius and h is the height of the cylinder.

Applying the concept:

Step 1: We need to find the volume of full cylinder with the given dimensions using the formula.

Volume of full cylinder =\pi r^{2} h=\pi* 8^{2} *9=576\pi cm^{3}

Volume of half cylinder =\frac{576\pi }{2} =288\pi cm^{3}

Step 2: Let x be the number of minutes of filling the sand.

6 cm^{3} of sand filled every 15 seconds, there are four 15 seconds in a minute.

So volume of sand filled in 1 minute= 6*4 cm^{3} = 24 cm^{3}.

8 cm^{3} of sand taken out of cylindrical vase every minute.

Net volume of sand filled in 1 minute = Volume of sand filled in the vase in one minute - Volume of sand taken out in 1 minute

Net volume of sand filled in 1 minute=24 cm^{3} - 8cm^{3}=16cm^{3}

Volume of sand filled in x minutes = 16x.

We need to set up an equation to find the number of minutes need to fill half the volume in cylindrical vase.

16x = 288\pi \\ \\ x=\frac{288\pi}{16}  \\ \\ x=18\pi \\ \\ x=57 minutes

Conclusion:

The number of minutes required for the base be half filled with sand is 57

6 0
3 years ago
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