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Alekssandra [29.7K]
3 years ago
5

Solve to indicated variable 16ak=-5 for a

Mathematics
1 answer:
damaskus [11]3 years ago
3 0
The answer is
\frac{ - 5}{16k}  = a
steps
#1) Try to leave a by itself by dividing any variable next to it
\frac{16 ak  =  - 5 }{ 16k}
you can only divided these variables as all these variables in the original equation. are being multiplied. The opposite if multiplication is division.
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The capacity of a jug is 6L. Kerry needs 5L of juice for a party. how many jugs will she have to make?
zimovet [89]

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Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
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So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

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\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

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2 years ago
Simplify the rational expression.  State any restrictions on the variable.
AveGali [126]

Answer:

The last choice.

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\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}

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