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Viefleur [7K]
3 years ago
14

How many yards are in 2.28 meters

Chemistry
1 answer:
bixtya [17]3 years ago
5 0
2.49 yards is the answer
You might be interested in
What is the mass, in grams, of 1.50 mol of iron (III) sulfate? Express your answer using three significant figures. mm = nothing
Paul [167]

<u>Answer:</u>

<u>For A:</u> The mass of iron (III) sulfate is 600. g

<u>For B:</u> The moles of ammonium carbonate is 0.07216 moles

<u>For C:</u> The mass of given number of molecules of aspirin is 0.359 grams.

<u>For D:</u> The molar mass of diazepam is 284.7 g/mol

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For A:</u>

We are given:

Number of moles of iron (III) sulfate = 1.50 mol

Molar mass of iron (III) sulfate = 399.9 g/mol

Putting values in equation 1, we get:

1.50mol=\frac{\text{Mass of iron (III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron (III) sulfate}=(1.50mol\times 399.9g/mol)=600.g

Hence, the mass of iron (III) sulfate is 600. g

  • <u>For B:</u>

We are given:

Mass of ammonium carbonate = 6.935 g

Molar mass of ammonium carbonate = 96.1 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonium carbonate}=\frac{6.935g}{96.1g/mol}=0.07216mol

Hence, the moles of ammonium carbonate is 0.07216 moles

  • <u>For C:</u>

We are given:

Number of aspirin molecules = 1.20\times 10^{21}

Mass of 1 mole of aspirin = 180.16 g/mol

According to mole concept:

6.022\times 10^{23} number of molecules occupies 1 mole

So, 6.022\times 10^{23} number of molecules of aspirin has a mass of 180.16 grams

Thus, 1.20\times 10^{21} number of molecules of aspirin will have a mass of \frac{180.16g}{6.022\times 10^{23}}\times 1.20\times 10^{21}=0.359g

Hence, the mass of given number of molecules of aspirin is 0.359 grams.

  • <u>For D:</u>

We are given:

Moles of diazepam = 0.05570 mol

Given mass of diazepam = 15.86 g

Putting values in equation 1, we get:

0.05570mol=\frac{15.86g}{\text{Molar mass of diazepam}}\\\\\text{Molar mass of diazepam}=\frac{15.86g}{0.05570mol}=284.7g/mol

Hence, the molar mass of diazepam is 284.7 g/mol

6 0
3 years ago
A chemist who studies water samples did a demonstration of how to test for lead in water. She added a clear solution of potassiu
faust18 [17]

Answer:

The swirling yellow solid formed is lead iodide (PbI₂).

Explanation:

The reaction of potassium iodide (KI) with lead nitrate (Pb(NO₃)₂) will produce lead iodide (PbI₂) and potassium nitrate (KNO₃) according to the equation:

2KI + Pb(NO₃)₂ → PbI₂↓ + 2KNO₃

Lead iodide (PbI₂) is a yellow swirling precipitate that is formed from the reaction.

<h2><u><em>☺☻</em></u></h2>
6 0
4 years ago
Read 2 more answers
12. How much mass is in a 3.25-mole sample of NH 4 OH? A. 10.8 g B. 34.0 g C. 35.1 g D. 114 g
Galina-37 [17]

Answer:

D. 114 g

Explanation:

  • NH4OH molecular weight. Molar mass of NH4OH = 35.0458 g/mol This compound is also known as Ammonium Hydroxide.
  • Convert grams NH4OH to moles or moles NH4OH to grams. Molecular weight calculation: 14.0067 + 1.00794*4 + 15.9994 + 1.00794.
8 0
3 years ago
Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

3 0
3 years ago
Acetylene burns in air according to the following equation: C2H2(g) + 5 2 O2(g) → 2 CO2(g) + H2O(g) ΔH o rxn = −1255.8 kJ Given
professor190 [17]

Answer:  -227 kJ

Explanation:

The balanced chemical reaction is,

C_2H_2(g)+\frac{5}{2}O_2(g)\rightarrow 2CO_2(g)+H_2O(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+ n_{H_2O}\times \Delta H_{H_2O})]-[(n_{C_2H_2}\times \Delta H_{C_2H_2})+(n_{O_2}\times \Delta H_{O_2})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-1255.8=[(2\times -393.5)+(1\times -241.8)]-[(1\times \Delta H_{C_2H_2})+(\frac{5}{2}\times 0)]

-1255.8=[(-787)+(-241.8)]-[(1\times \Delta H_{C_2H_2})+(0)]

\Delta H_{C_2H_2}=-227kJ

Therefore, the enthalpy change for C_2H_2 is -227 kJ.

7 0
3 years ago
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