Question

What is the mass, in grams, of 1.50 mol of iron (III) sulfate? Express your answer using three significant figures. mm = nothing g Request Answer Part B How many moles of ammonium ions are in 6.935 g of ammonium carbonate? Express your answer using four significant figures. nn = nothing mol Request Answer Part C What is the mass, in grams, of 1.20×1021 molecules of aspirin, C9H8O4? Express your answer using three significant figures. mm = nothing g Request Answer Part D What is the molar mass of diazepam (Valium®) if 0.05570 mol weighs 15.86 g? Express your answer using four significant figures. MM = nothing g/mol

Answer 1

Answer:

For A: The mass of iron (III) sulfate is 600. g

For B: The moles of ammonium carbonate is 0.07216 moles

For C: The mass of given number of molecules of aspirin is 0.359 grams.

For D: The molar mass of diazepam is 284.7 g/mol

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

• For A:

We are given:

Number of moles of iron (III) sulfate = 1.50 mol

Molar mass of iron (III) sulfate = 399.9 g/mol

Putting values in equation 1, we get:

$1.50mol=\frac{\text{Mass of iron (III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron (III) sulfate}=(1.50mol\times 399.9g/mol)=600.g$

Hence, the mass of iron (III) sulfate is 600. g

• For B:

We are given:

Mass of ammonium carbonate = 6.935 g

Molar mass of ammonium carbonate = 96.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonium carbonate}=\frac{6.935g}{96.1g/mol}=0.07216mol$

Hence, the moles of ammonium carbonate is 0.07216 moles

• For C:

We are given:

Number of aspirin molecules = $1.20\times 10^{21}$

Mass of 1 mole of aspirin = 180.16 g/mol

According to mole concept:

$6.022\times 10^{23}$ number of molecules occupies 1 mole

So, $6.022\times 10^{23}$ number of molecules of aspirin has a mass of 180.16 grams

Thus, $1.20\times 10^{21}$ number of molecules of aspirin will have a mass of $\frac{180.16g}{6.022\times 10^{23}}\times 1.20\times 10^{21}=0.359g$

Hence, the mass of given number of molecules of aspirin is 0.359 grams.

• For D:

We are given:

Moles of diazepam = 0.05570 mol

Given mass of diazepam = 15.86 g

Putting values in equation 1, we get:

$0.05570mol=\frac{15.86g}{\text{Molar mass of diazepam}}\\\\\text{Molar mass of diazepam}=\frac{15.86g}{0.05570mol}=284.7g/mol$

Hence, the molar mass of diazepam is 284.7 g/mol