Answer:
Explanation:
Group 4A contains a total of 4 electrons for each atom in their valence shell. Filling the orbital diagram, let's say, for carbon, notice that when we start with period 2, we have two elements in the s-block, that is, lithium and beryllium. They correspond to the two s electrons that belong to the valence shell of carbon.
Moving on, we have boron and carbon, the remaining 2 electrons. Now, starting with boron, we're in the p-block.
That said, looking at the second period, the electron configuration for the valence shell of a group 4A element would be:
Answer:
a) heat it from 23.0 to 78.3
q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =
b) boil it at 78.3
(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =
c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ
Explanation:
Answer:
See below
Step-by-step explanation:
1. Colloid
B) Microscopic insoluble particles that are suspended throughout another substance.
Milk is a colloid. It consists of small fat globules suspended in water.
2. Emulsion
D) Two or more liquids that are not normally mixable.
Mayonnaise is an emulsion. It consists of oil, egg yolks, vinegar, and seasonings. Normally, the oil and vinegar (95 % water) do not mix. Without the egg yolk , they would quickly separate. Egg yolk contains the emulsifier, lecithin, which is attracted to both oil and water and stabilizes he mixture.
3. Solution
A) A solute that is evenly distributed within the solvent.
Sugar syrup is a solution of sugar in water.
4)Homogeneous
C) A mixture that has its components distributed evenly within the substance.
A homogeneous mixture has only one phase. For example, the sugar syrup is homogeneous, because, even with a powerful microscope, you can't see a boundary between the sugar particles and the water.
Answer:
yes
Explanation:
it affects the bluebirds habitat
Answer : The volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.
Explanation :
Let the volume of sodium benzoate (salt) be, x
So, the volume of benzoic acid (acid) will be, (100 - x)
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:
x = 29.0
The volume of sodium benzoate = x = 29.0 mL
The volume of benzoic acid (acid) = (100 - x) = (100 - 29.0) = 71 mL
Thus, the volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.
