In quadrilateral QRST, QS = RT.IS QRST a rectangle?<br> a:no<br> b:cannot be determined <br> c:yes

vOfficials at a major university wanted to know what percent of their students recycle paper. They conducted a random survey and

Svetllana [295]

Answer:

The probability is 0.95

Step-by-step explanation:

In this question, we are interested in calculating the probability that a randomly selected student of the university recycles at least some of the times

Mathematically, the probability that student recycles at least some of time = 1 - probability that the student never recycles all the time

From the question, the probability that the student never recycles all the time = 0.05

Substituting this into the equation given above;

Probability that a randomly selected student at the university recycles at least some of the time = 1-0.05 = 0.95

6 0

3 years ago

Please help - Solve<br> -103=6x+17

Mazyrski [523]

Answer:

its Ans is x= -20......

5 0

2 years ago

Read 2 more answers

Josie saw a sign advertising 6 ears of sweet corn for $1.50. how much would 15 ears of corn cost?

Arlecino [84]

$1.50/6= $0.25
$0.25* 15= $3.75

5 0

3 years ago

Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of

forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

$n = 120, \pi = \frac{58}{120} = 0.4833$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001$

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0

3 years ago

Whats the powerpoint equation to 86.4

astraxan [27]

Answer:

26 (:

Hope this helps

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In quadrilateral QRST, QS = RT.IS QRST a rectangle? a:no b:cannot be determined c:yes