Matter doesn't have to take up space as long as it has mass.

Chemistry

2 answers:

____ [38]3 years ago

7 0

Answer:

Matter always takes space (or has volume).

baherus [9]3 years ago

4 0

Answer:

False. Everything that has mass takes up space.

Explanation:

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EXPLAIN how to identify the reducing agent in a reaction of magnesium with oxygen

Alina [70]

Explanation:

Mg+O>MgO

Here the mg loses it electron and is oxidised and oxygen gains and is reduced.

Mg(2+)and O(2-)

Mg is a reducing agent it makes oxygen to be reduced while itself being oxidised and vice versa.

8 0

2 years ago

Please help ASAP please and thanks!! I'll also mark you!

skelet666 [1.2K]

Substitution Reactions are those reactions in which one nucleophile replaces another nucleophile present on a substrate. These reactions can take place via two different mechanism i.e SN¹ or SN². In SN¹ substitution reactions the leaving group leaves first forming a carbocation and nucleophile attacks carbocation in the second step. While in SN² reactions the addition of Nucleophile and leaving of leaving group take place simultaneously.

Example:
OH⁻ + CH₃-Br → CH₃-OH + Br⁻

In above reaction,

OH⁻ = Incoming Nucleophile

CH₃-Br = Substrate

CH₃-OH = Product

Br⁻ = Leaving group

Organic reactions are typically slower than ionic reactions because in organic compounds the covalent bonds are first broken, this breaking of bonds is a slower step, while, in ionic compounds no bond breakage is required as it consists of ions, so only bond formation takes place which is a quicker and fast step.

7 0

3 years ago

List three examples of high energy waves that are harmful to living things:

lord [1]

UV rays, gamma rays, and x rays
Hope this help

5 0

3 years ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol