Answer:
Percent yield = 22.26%
Explanation:
Given data:
Mass of lithium nitride = 105 g
Mass of lithium hydroxide produces = 48 g
Percent yield = ?
Solution:
Chemical equation:
Li₃N + 3H₂O → 3LiOH + NH₃
Number of moles of lithium nitride :
Number of moles = mass/ molar mass
Number of moles = 105 g/ 34.83 g/mol
Number of moles = 3 mol
Now we will compare the moles of lithium nitride with lithium hydroxide.
Li₃N : LiOH
1 : 3
3 : 3×3 = 9 mol
Mass of lithium hydroxide:
Mass = number of moles × molar mass
Mass = 9 mol × 23.95 g/mol
Mass = 215.6 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 48 g/ 215.6 g × 100
Percent yield = 22.26%
Answer:
The valency of Aluminium (Al) is +3 whereas, the valency of Chlorine is -1.
Explanation:
Valency is not defined for a compound. It is only for elements. Basically, valency is the combining or replacing power of an hydrogen atom of a certain element with an other atom of element.
Answer:
6.25 g
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Original amount (N₀) = 200 g
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Number of half-lives (n) =
n = t / t½
n = 344 / 68.8
n = 5
Thus, 5 half-lives has elapsed.
Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:
Original amount (N₀) = 200 g
Number of half-lives (n) = 5
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2⁵ × 200
N = 1/32 × 200
N = 200 / 32
N = 6.25 g
Thus, the amount of Uranium-232 that remains is 6.25 g
Answer:
CnH2n+2 formula
Explanation:
Alkanes have the general formula CnH2n+2, so if an alkane had 7 carbon atoms, it would have the molecular formula C7H16.