Mykel is planning a banquet for 125 guests. He needs to select 4 appetizers, 2 entrees, and 4 side dishes. Carson's Catering has
15 appetizers, 10 entrees, and 11 side dishes to choose from. How many different ways are there for Mykel to plan the menu?
1 answer:
Answer:
20,270,250 ways
Step-by-step explanation:
Mykel needs to select 4 appetizers from 15 appetizers. So number of ways to select this is; 15C4 = 1365 ways
Mykel needs to select 2 entrees from 10 entree. So number of ways to select this is; 10C2 = 45 ways
Mykel needs to select 4 side dishes from 11 side dishes. So number of ways to select this is;11C4 = 330 ways
Thus,total number of ways Mykel can plan the menu = 1365 × 45 × 330 = 20270250 ways
You might be interested in
This can be found by finding 44 chosen 5 at a time times 1/32.
That would be
44! / (44-5)!(5!) * 32 =
1 chance in 34,752,256
To do this you want to divide 110 by 5 to get 22. Now you want to multiply 3 by 22. That means the caterer need 66 pounds of tomatoes.
I'm not to sure maybe b ?
Answer:
Step-by-step explanation:
1) a = x - 5
a) z = y + 5
b) z = y - 3
c) z = 6y
d) z = 6y - 2
e) z = 3y + 5
nice day folks eeeeeeeeeeeeeeeee
