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densk [106]
3 years ago
5

Mykel is planning a banquet for 125 guests. He needs to select 4 appetizers, 2 entrees, and 4 side dishes. Carson's Catering has

15 appetizers, 10 entrees, and 11 side dishes to choose from. How many different ways are there for Mykel to plan the menu?
Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

20,270,250 ways

Step-by-step explanation:

Mykel needs to select 4 appetizers from 15 appetizers. So number of ways to select this is; 15C4 = 1365 ways

Mykel needs to select 2 entrees from 10 entree. So number of ways to select this is; 10C2 = 45 ways

Mykel needs to select 4 side dishes from 11 side dishes. So number of ways to select this is;11C4 = 330 ways

Thus,total number of ways Mykel can plan the menu = 1365 × 45 × 330 = 20270250 ways

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Martin charges $15 for every 5 bags of leaves he rakes. Last weekend, he raked 29 bags of leaves. How much money did he earn?
laila [671]

Answer:

87 or 75 dollars

Step-by-step explanation:

So first we have to 29 by 5 wich gives us 5.8 so he raked 5.8 packs of 5 bags then you multiply 15 by 5.8 so he made 87 dollars

Unless:

Your not counting the point 8 leaves in that case the answer would be 75

8 0
3 years ago
A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
3 years ago
What is the product?<br> (2x - 1)(x+4)<br> 2²-4<br> 2x²+4<br> 2x^2+7x-4<br> 2x^2-7x-4
SVETLANKA909090 [29]
2x^2 -7x -4 is the answer
7 0
4 years ago
math and science. during winter months, freshwater fish sense the water getting colder and swim to the bottoms of lakes and rive
Aleksandr-060686 [28]
28 feet

32 feet divided by 8 equals 4
so the lake is in sections of 4
take 4 times it by 7
answer is 28 feet

to check your answer 28/32 simplified is 7/8
8 0
4 years ago
Read 2 more answers
Simplify the expression (5 3i) (4-4i) a. 8i b. 9-i c. 9 i d. 9-7i
poizon [28]
The expression will be d. 9-7i
8 0
3 years ago
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