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densk [106]
3 years ago
5

Mykel is planning a banquet for 125 guests. He needs to select 4 appetizers, 2 entrees, and 4 side dishes. Carson's Catering has

15 appetizers, 10 entrees, and 11 side dishes to choose from. How many different ways are there for Mykel to plan the menu?
Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

20,270,250 ways

Step-by-step explanation:

Mykel needs to select 4 appetizers from 15 appetizers. So number of ways to select this is; 15C4 = 1365 ways

Mykel needs to select 2 entrees from 10 entree. So number of ways to select this is; 10C2 = 45 ways

Mykel needs to select 4 side dishes from 11 side dishes. So number of ways to select this is;11C4 = 330 ways

Thus,total number of ways Mykel can plan the menu = 1365 × 45 × 330 = 20270250 ways

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Answer:

1. How many will be infected next week

From the information, there are 1000 mice in the lab.

200 mice are infected. It is expected that 90% of the mice are expected to overcome the infection and 40% uninfected mice will be infected.

If 200 mice are infected, then number of uninfected mice is:

= 1000 - 200 = 800

90% of infected mice get cured. Out of 200 mice who are infected, the number of mice getting cures is:

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The number of mice still infected is 200 - 180 = 20

Out of 800 uninfected mice, 40% will get infected. Number of infected mice is:

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2. How many will be infected in 3 weeks

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Out of 660 mice, 40% will be infected. The number of mice becoming infected is

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3 years ago
Please help me with vivid explanation​
Ivanshal [37]

Answer:

864 m²

Step-by-step explanation:

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The area of a rectangle is given by the product of the length and the width

let A be the total area

A = 100*120

A = 12000 m²

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Let A"' be the area of the road

A"' =A-A'

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