Answer:
50% of their children are likely to be carriers of cystic fibrosis
Explanation:
Since the normal allele "F" will be the dominant allele while the mutated CFR allele "f" will be the recessive allele, <u>the gene (pair of alleles) of the person that is a CFR carrier will be "Ff" while that of the normal person who isn't a carrier will be "FF"</u>. The attachment shows the crossing between the two parents. From the illustration in the attachment, for every 4 children given birth to, 2 of them will likely be normal, "FF", (not a carrier and doesn't have cystic fibrosis) while 2 others will likely be carriers of cystic fibrosis (Ff). Hence, 50% of their children are likely to be carriers of cystic fibrosis.
First figure has the lowest pitch
B. More studies will take place on the issue
is the most likely outcome.
Answer:
The answer is C : The fossil in layer Y is older than the fossil in layer W