3 years ago

11. During a thunderstorm, 143 out of 333

Mathematics

1 answer:

serious [3.7K]3 years ago

8 0

Answer:

a).429 with all numbers repeating

b)They all repeat

You might be interested in

If triangle ABC is Congruent with triangle DEF the length of side DE is:

amid [387]

AB is congruent to side DE.

So,

AB= 23 and DE= 23

I hope this helps!
~kaikers

5 0

3 years ago

Read 2 more answers

Can you help me please

Alina [70]

Answer:

120 in²

Hope this helps!

3 0

2 years ago

Read 2 more answers

How do i find the negative exponent

sesenic [268]

Answer:

always 1

Step-by-step explanation:

5 0

3 years ago

Let's say that your sibling babysat your neighbor for 1 hour and earned $12, and on another night you babysat the same neighbor

irinina [24]

Answer:

uy would ve usjebbvdhbxjejkeke

3 0

3 years ago

A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe

Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

$\omega=\frac{v}{r}$ ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

$47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}$

next, you replace the values of v and r in the equation (1):

$\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}$

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0

3 years ago