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2 years ago

#2 What is the equation of the horizontal asymptote for the following exponential graph?

Mathematics

1 answer:

Softa [21]2 years ago

5 0

Answer:

y = -1

Step-by-step explanation:

We are looking for the horizontal line which the function approaches but never meets;

This is y = -1

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6=−w8 how can i solve this

Vaselesa [24]

Divide 6 by -8 to get the variable alone!
6/-8 < division< equation

4 0

3 years ago

The coefficient of -x is 1

juin [17]

Answer:

it -1

Step-by-step explanation:

3 0

3 years ago

APT4PTO

inysia [295]

Answer:

1536 square inches

Step-by-step explanation:

In units of 5 feet, the backdrop is 3 units wide and 2 units high, for a total area of 3×2 = 6 square units.

Those same units on the scale drawing are each 16 inches. One square unit on the scale drawing is (16 in)² = 256 in². So, 6 of them have an area of ...

6 × 256 in² = 1536 in²

6 0

2 years ago

5+2 root 3 / 7+4 root 3 =a-6root3

STALIN [3.7K]

Answer:

Step-by-step explanation:

$\dfrac{5+2\sqrt3}{7+4\sqrt3}\qquad\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=\dfrac{5+2\sqrt3}{7+4\sqrt3}\cdot\dfrac{7-4\sqrt3}{7-4\sqrt3}=\dfrac{(5+2\sqrt3)(7-4\sqrt3)}{7^2-(4\sqrt3)^2}\qquad\text{use FOIL}\\\\=\dfrac{(5)(7)+(5)(-4\sqrt3)+(2\sqrt3)(7)+(2\sqrt3)(-4\sqrt3)}{49-4^2(\sqrt3)^2}\\\\=\dfrac{35-20\sqrt3+14\sqrt3-8(3)}{49-(16)(3)}=\dfrac{(35-24)+(-20\sqrt3+14\sqrt3)}{49-48}\\\\=\dfrac{11-6\sqrt3}{1}=11-6\sqrt3$

8 0

3 years ago

Help...this is due in a few hours

Mrrafil [7]

Answer:

Step-by-step explanation:

14+7=21.

You do this to allow you to get that outcome, because you know 7*7=49.

Therefore 21-14=7

7*-7=49

6 0

2 years ago