Answer:
○![\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%5C%3A%5Bor%5C%3A-%5Cfrac%7B2%7D%7B%5Csqrt%7B3%7D%7D%5D)
Step-by-step explanation:
You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of
which gives you 
Extended Information

![\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%20%3D%20%5B-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D%5E%7B-1%7D)
I am joyous to assist you anytime.
Answer:
n=11
Step-by-step explanation:
5n-3n=18+4
2n=22
n=22/2
n=11
73. Area- 55 Perimeter-32
75. Area-30 Perimeter-30
Step-by-step explanation:
A1=8
A2=A1+5 plug 8 into A1 here. After getting the value, put into next equation. And repeat until you get A5
A3=A2+5
A4=A3+5
A5=A4+5
Here is the answer to ur question :) Hope this helps!