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3 years ago

Need help pls 8th math

Mathematics

1 answer:

finlep [7]3 years ago

3 0

I am not completely sure but it's most likely the last option because congruent means equal and the two trapezoids can't be equal because of the different side lengths.

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A inverse variation has a k value of 8 which order pair is on the graph of the function

Nikolay [14]

Y = k / x
2 = k / 4
k = 8

Therefore, the answer for this question would be (4,2)

5 0

4 years ago

Write your answer in simplest radical form

Akimi4 [234]

Answer:

s = 17

Step-by-step explanation:

Using the tangent ratio in the right triangle and the exact value

tan60° = $\sqrt{3}$ , then

tan60° = $\frac{opposite}{adjacent}$ = $\frac{17\sqrt{3} }{s}$ = $\sqrt{3}$ ( multiply both sides by s )

s × $\sqrt{3}$ = 17 $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

s = 17

4 0

3 years ago

Simplify the expression and find the value, if x=2 : 5x-6-x+9

timurjin [86]

Answer:11

Step-by-step explanation:

5x-6-x+9

When x=2 we have

5(2)-6-2+9

10-6-2+9

10+9-6-2

19-6-2=11

6 0

3 years ago

Read 2 more answers

Two points are separated on the ground by a distance of 43 km. Can they be placed on a 1 / 25000th map with dimensions 1.32 m on

Wittaler [7]

Answer:

Explanation:

The distance between the two points on the ground = 43km

$\text{Scale}=\frac{1}{25000}$

First, we calculate the distance between the two points in meters.

• 43km = 43,000 m.

Next, determine the distance it will take using the scale.

$\begin{gathered} \frac{1}{25000}=\frac{x}{43000} \\ 25000x=43000 \\ x=\frac{43000}{25000} \\ x=1.72m \end{gathered}$

The distance between the points using the scale is 1.72m.

Next, we see that the dimensions (1.32 m by 0.85 m) are smaller than the length.

As a final check, calculate the length of the diagonal of the map. The diagonal is usually the longest part.

$\text{Diagonal}=\sqrt[]{1.32^2+0.85^2}=1.57m$

Since 1.57m is still less than 1.72m, the two points cannot be placed on the map.

7 0

1 year ago

The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi

kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0

3 years ago