Answer:
%Reduction in area = 73.41%
%Reduction in elongation = 42.20%
Explanation:
Given
Original diameter = 12.8 mm
Gauge length = 50.80mm
Diameter at the point of fracture = 6.60 mm (0.260 in.)
Fractured gauge length = 72.14 mm.
%Reduction in Area is given as:
((do/2)² - (d1/2)²)/(do/2)²
Calculating percent reduction in area
do = 12.8mm, d1 = 6.6mm
So,
%RA = ((12.8/2)² - 6.6/2)²)/(12.8/2)²
%RA = 0.734130859375
%RA = 73.41%
Calculating percent reduction in elongation
%Reduction in elongation is given as:
((do) - (d1))/(d1)
do = 72.14mm, d1 = 50.80mm
So,
%RA = ((72.24) - (50.80))/(50.80)
%RA = 0.422047244094488
%RA = 42.20%
 
        
             
        
        
        
Answer:
 14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s 
inlet temp = 30°C + 273 = 303 k 
cooling medium temperature = 6°C  + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s 
Determine the outlet temperature 
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water 
= ( Mcp ( To - 6 )  =  Mcp ( 30 - To ) 
since the properties of water and the cooling medium ( water ) is the same 
= 0.02 ( To - 6 ) = 0.011 ( 30 - To ) 
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C
 
        
             
        
        
        
Answer:
In refrigeration cycle heat transfer from inside refrigeration
In heat pump cycle heat transfer from environment
Explanation:
heat cycle is mechanical process use for cool the temperature but
In refrigeration heat transfer from inside of refrigeration that decrease temperature of refrigerator and in heat pump it decrease temperature negligible as compare to refrigerator 
 
        
             
        
        
        
Answer:
(A) and (D)
Explanation:
1) P2 is less than P1, that is when P1 increases in pressure, the velocity V1 of the water also increases. Therefore, on the other hand, since P2 is directly proportional to V1, P2 and V2 will be less than P1 and V1 respectively.
2) For P2 greater than P1 and V2 also is greater than V1. Since P2 is directly proportional to V2, hence, when P2 increases in pressure, P1 reduces in pressure. Similarly, velocity, V2 also increases and V1 reduces. 
 
        
             
        
        
        
<u>Answer:</u>
<u>of 150 pounds per square inch</u>
Explanation:
Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>
In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.