The sample of 81 students was selected with a mean score of 90, this illustrates an example of a right tailed one sample z test.
<h3>How to illustrate the sample?</h3>
From the information given, the teacher claims that the mean score of students in his class is greater than 82 with a standard deviation of 20. In this case, the right tailed one sample z test is used.
The z value will be:
= (90 - 82)/20/✓81
= 3.6
Since 3.6 > 1.645, the null hypothesis will be rejected as there's enough evidence to support the teacher's claim.
When an online medicine shop claims that the mean delivery time for medicines is less than 120 minutes with a standard deviation of 30 minutes, the left tailed one sample test is used.
The z value will be:
= (100 - 120)/(30/✓49)
= -4.66
The null hypothesis is rejected as there is enough evidence to support the claim of the medicine shop.
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Answer:
Digestion
1 is correct since you need to eat something before anything else.
2 is incorrect since if this was first, what are you storing?
3 is incorrect since that is the second thing you need to do.
4 is incorrect since that is the last thing to do.
Leading/trailing shoe type drum brake This is called the servo effect (self-boosting effect) which realizes the powerful braking forces of drum brakes. ... This is because drum brakes generate the same braking force in either direction. Generally, this type is used for the rear brakes of passenger cars.
Answer:
Percent Elongation = 52.72%
Percent Reduction in Area = 64%
Explanation:
First we find percent elongation:
Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%
Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%
<u>Percent Elongation = 52.72%</u>
Now, for the percent reduction in area:
Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%
Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%
<u>Percent Reduction in Area = - 64%</u>
here, negative sign shows a decrease in area.
Answer: Increase in the population of lower organisms.
Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.
They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.
Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.
