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3 years ago

What is the value of the work interaction in this process?

Engineering

1 answer:

Cloud [144]3 years ago

7 0

Answer:

The answer is " $-121\ \frac{KJ}{Kg}$ ".

Explanation:

Please find the correct question in the attachment file.

using formula:

$\to W=-P_1V_1+P_2V_2 \\\\When \\\\\to W= \frac{P_1V_1-P_2V_2}{n-1}\ \ or \ \ \frac{RT_1 -RT_2}{n-1}\\\\$

$W =\frac{R(T_1 -T_2)}{n-1}\\\\$

$=\frac{0.287(25 -237)}{1.5-1}\\\\=\frac{0.287(-212)}{0.5}\\\\=\frac{-60.844}{0.5}\\\\=-121.688 \frac{KJ}{Kg}\\\\=-121 \frac{KJ}{Kg}\\\\$

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A 8-core machine has 4 times the performance of a single-core machine of the same frequency. Performance is proportional to freq

tankabanditka [31]

Answer: The 8-core machine saves 87.5% of the dynamic power.

Explanation:

Let Fold = f , Vold = V , Cold = Capacitance

Old Dynamic power = Cold × (Vold × Vold) × f

therefore for the 8-core machine

Fnew / Fold = 1/4

Fnew = Fold/4

we were told that Voltage decreases proportional to frequency,

Vnew / Vold = 1/4

Vnew = V / 4

So New Capacitance will be;

Cnew = Cold

Thus, New Dynamic power = 8 × Cnew × ( Vnew × Vnew ) × Fnew

= 8 × Cold × (Vold × Vold/16) × ( f/4 )

= 8 × ( Cold ) × ( Vold × Vold ) × ( f ) / 64

= (Old Dynamic Power) / 8

therefore

Old Dynamic Power / New Dynamic Power = 8

Thus, Percentage of power saved will be;

Percentage power saved = 100 × ( Old Dynamic Power - New Dynamic Power ) / Old Dynamic Power

= 100 × (8-1) / 8

= 87.5 %

Therefore The 8-core machine saves 87.5% of the dynamic power.

6 0

3 years ago

Consider a unidirectional continuous fiber-reinforced composite with epoxy as the matrix with 55% by volume fiber.i. Calculate t

ohaa [14]

Answer:

I)E= 40.95 GPa

II)E=5.29 GPa

Explanation:

Given that

E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45

E₂ = 72.5 GPa ,V₂=0.55

Longitudinal moduli given as ;

E= E₁V₁+E₂V₂

E= 2.41 x 0.45 + 72.5 x 0.55 GPa

E= 40.95 GPa

II)

E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45

E₂ =230 GPa ,V₂=0.55

Transverse moduli given as:

$\dfrac{1}{E}=\dfrac{V_1}{E_1}+\dfrac{V_2}{E_2}$

$\dfrac{1}{E}=\dfrac{0.45}{2.41}+\dfrac{0.55}{230}$

E=5.29 GPa

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3 years ago

1) Pareto charts are used to: A) identify inspection points in a process. B) outline production schedules. C) organize errors, p

zloy xaker [14]

Answer:

E) Please see below as the answer is self -explanatory.

Explanation:

The pareto chart, is used in quality control, and is a combined type of graph, that uses a line-type curve to denote the cumulative percentages of the different types of defects found in a sample (so the maximum value is 100%)

Also, it features a bar chart, which shows the relative occurrence of the different values (as in a histogram) which allows to find easily which defects are more relevant ones, alerting in this way about unacceptable deviations in the manufacturing process (if we are producing a good under given quality standards, for instance).

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3 years ago

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aleksklad [387]

Answer:

Your house is in need of a service upgrade, or it may indicate that your house has too few circuits.

Explanation:

It's a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits.

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frez [133]

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