Question

7c + 7a - 7r + 8m + 2y=31solve for c a r m and y​

Answer 1

For this case we have the following equation:

$7c + 7a-7r + 8m + 2y = 31$

We solve for c:

We pass the terms that do not contain "c" to the other side of the equation by changing signs:

$7c = 31-7a + 7r-8m-2y$

We divide by 7 on both sides of the equation:

$c = \frac {31-7a + 7r-8m-2y} {7}$

We solve for "a":

We pass the terms that do not contain "a" to the other side of the equation by changing signs:

$7a = 31-7c + 7r-8m-2y$

We divide by 7 on both sides of the equation:

$a = \frac {31-7c + 7r-8m-2y} {7}$

We solve for r:

We pass the terms that do not contain "r" to the other side of the equation by changing signs:

$-7r = 31-7c-7a-8m-2y$

We multiply by -1 on both sides:

$7r = 7c + 7a + 8m + 2y-31$

We divide by 7 on both sides of the equation:

$r = \frac {7c + 7a + 8m + 2y-31} {7}$

We solve for m:

We pass the terms that do not contain "m" to the other side of the equation by changing signs:

$7c + 7a-7r + 8m + 2y = 31\\8m = 31-7c-7a + 7r-2y$

We divide by 7 on both sides of the equation:

$m = \frac {31-7c-7a + 7r-2y} {8}$

We solve for y:

We pass the terms that do not contain "y" to the other side of the equation by changing signs:

$2y=31-7c-7a+7r-8m$

We divide by 2 on both sides of the equation:

$y=\frac{31-7c-7a+7r-8m}{2}$

Answer:

$c = \frac {31-7a + 7r-8m-2y} {7}$

$a = \frac {31-7c + 7r-8m-2y} {7}$

$r = \frac {7c + 7a + 8m + 2y-31} {7}$

$m = \frac {31-7c-7a + 7r-2y} {8}$

$y=\frac{31-7c-7a+7r-8m}{2}$