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Mazyrski [523]
4 years ago
8

How many cookies did the baker make before he opened the store? WILL GIVE BRAINLIEST

Mathematics
2 answers:
laiz [17]4 years ago
8 0
10  7/12 dozens of cookies
hope this helps
Anarel [89]4 years ago
6 0
2 3/4 + 3 1/2 + 4 1/3= 

10 7/12 cookies 
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Car insurance companies want to keep track of the average cost per claim. The current data in use for Auto Insurance R Us is an
eduard
I just took the test, the answer is 5%.
5 0
3 years ago
Read 2 more answers
F(x) = x² + 7<br> X(-2) =
gizmo_the_mogwai [7]

Answer:

hope it will help you

Step-by-step explanation:

f(x)=x²+7

X(-2)=?

therefore X(-2)=(-2)²+7

=4+7

=11

4 0
4 years ago
What is the square root of –16?<br><br><br><br> –8i<br><br> –4i<br><br> 4i<br><br> 8i
Ad libitum [116K]

we know that

i^{2} =-1

we have

\sqrt{-16} =\sqrt{(-1)*(16)} =\sqrt{(-1)*(4^{2})}

substitute the value of i^{2}=-1 in the expression above

\sqrt{(-1)*(4^{2})}=\sqrt{i^{2}*4^{2}} \\ \\= 4i

therefore

<u>the answer is</u>

4i


7 0
4 years ago
Read 2 more answers
Find the resultant matrix ~
aev [14]

                    \left[\begin{array}{ccc}5\\3\\2\end{array}\right] \times[5 \ \ \ 3 \ \ \ 2]

Matrix multiplications are defined if the number of columns in the first matrix is equal to the number of rows in the second matrix.

                    \bf{\left( \begin{array}{rrr} 5  \\ 3  \\ 2  \end{array}\right) \ \ (5 \ \ 3 \ \ 2)}

Multiply the first element of the array by the first element of the second array to get the element of the first row of the first column in the product array.

                    \bf{\left( \begin{array}{rrr} 5\times5 &  &  \\  &  &  \\  &  &  \end{array}\right)}

The remaining elements of the product matrix are obtained in the same way.

                        \bf{ \left( \begin{array}{rrr} 5\times5 & 5\times3 & 5\times2 \\ 3\times5 & 3\times3 & 3\times2 \\ 2\times5 & 2\times3 & 2\times2 \end{array}\right) }

Simplify each item by multiplying the individual terms.

                                 \left( \begin{array}{rrr} 25 & 15 & 10 \\ 15 & 9 & 6 \\ 10 & 6 & 4 \end{array}\right)

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

4 0
2 years ago
1) Para que valores reais de x o ponto P (3x -6, 2x +4) pertence ao 4º quadrante?
skelet666 [1.2K]

Answer:

There are no real values of x for point P to belong to the 4 quadrant

Step-by-step explanation:

<u><em>The question in English is</em></u>

To what real values ​​of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?

we know that

A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative

we have the point

P (3x-6, 2x+4)

3x-6 > 0 ----> inequality A  ( x-coordinate must be positive)

2x+4 < 0 ---> inequality B ( y-coordinate must be negative)

Solve Inequality A

3x-6 > 0

3x > 6

x > 2  -----> (2,∞)

Solve Inequality B

2x+4 < 0

2x < -4

x < -2 ----> (-∞,-2)

The solution of the system is

(-∞,-2) ∩ (2,∞)

therefore

The system has no solution

There are no real values of x for point P to belong to the 4 quadrant

3 0
4 years ago
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