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Thepotemich [5.8K]

3 years ago

15

The cost of vacation to a cabin resort for a night is $95 for each person. Each cabin also has to pay a $25 recreational equipme

nt rental fee. Model the cost, C, for staying x nights at the resort.

2 answers:

Rom4ik [11]3 years ago

8 0

x=95x+ 25

Step-by-step explanation:

Blababa [14]3 years ago

7 0

(x) = 95x + 25 is correct, since the $25 cost is fixed, but the $95 cost increases as x increases.

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Y intercept of y=2x-3

3241004551 [841]

Since the equation is in y = mx+b form you can easily determine the y intercept based on the b value present.

Y = mx + b
Y = 2x - 3
B = y intercept = (0,-3).

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3 years ago

Montano1993 [528]

Answer:

y = 0.5x + 3

Step-by-step explanation:

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2 years ago

Lilly and Maggie decorated their windows with twinkle lights. Maggie used 51 more twinkle lights than Lilly. Fill in the box wit

nadya68 [22]

We know that
m-------------------- > <span>the amount of twinkle lights Maggie used
l--------------------- > </span><span>the amount of twinkle lights Lilly used
l=70
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3 years ago

Ab - bc+ ac, bc - ca+ ab, ca - ab-2bc

BabaBlast [244]

Answer:

$ab-2bc+ca$

Step-by-step explanation:

Complete question is given below

Add:-

ab-bc+ac,bc-ca+ab,ca-ab-2bc

We have to find the result after addition

Now, adding all expression

We get

$ab-bc+ac+bc-ca+ab+ca-ab-2bc$

Combine like terms then, we get

$(ab+ab-ab)+(bc-bc-2bc)+(ac-ca+ca)$

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3 0

3 years ago

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .

4 0

3 years ago