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3 years ago

Multiple 1.229 by 15 and round to the nearest cent

1 answer:

7 0

When you multipy 1.229 x 15 your answer is 18.435. Rounding to the nearest cent will only include 2 numbers after the decimal. Looking at 18.435, the last number, 5 will round your answer to 18.44

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A number times 45 decreased by 12 is no more than 117

Kay [80]

Answer: n*4512 is less than or equal to 117

Step-by-step explanation: n=number N*45=X X=Number more than 117. X decreased by 12 is less than or equal to 117.

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3 years ago

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Goshia [24]

I would but I’m stuck on this problem too

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2 years ago

Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th

fgiga [73]

The values of data that might affect the statistical measures of spread and center is that: D. The males have a suspected significant high outlier.

<h3>What is a box and whisker plot?</h3>

A boxplot is also referred to as box and whisker plot and it can be defined as a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.

In Mathematics, the five-number summary of any box and whisker plot include the following:

Minimum
First quartile
Median
Third quartile
Maximum

By critically observing the box and whisker plots which represent the number of hours the students worked in summer jobs, we can reasonably infer and logically deduce that male students have a significant high outlier because the maximum value (37) is very far from the third quartile (15).

Read more on boxplots here: brainly.com/question/14277132

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6 0

1 year ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

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2 years ago

Need help with trig!

dedylja [7]

Answer:

1. A. $4.42$

2. F. $20.9$

3. G. $4.57$

4. A. $4.50$

Step-by-step explanation:

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3 years ago