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3 years ago

What is the volume of wax needed for the candle in the shape of a prism?

Mathematics

1 answer:

Vesnalui [34]3 years ago

6 0

Answer:

Step-by-step explanation:

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When an exponent is a negative number, we can think of it as taking the...?

STALIN [3.7K]

Answer:

We can think of it as the zeros after the decimal point.

Step-by-step explanation:

Negative exponents always move the number to the right putting the decimal in front of it.

5 0

3 years ago

Donna paid $3 to rent shoes and then $1 for each game she played at a bowling alley. She spent a total of $8 at the bowling alle

Alexxx [7]

Answer:If shoes are for all games in row, P = 2 + 3 g If not, P = 5 g ,with g the number of games

Explanation: The price depends:if shoes are included for the whole games, you just have to pay them once and then you have to pay

g g a m e s , so P ( g ) = 2 + 3 g Else, you have to pay g s h o e s and g b o w l p a r t y ,so

P ( g ) = 2g + 3 g⇔ P ( g ) = 5 g

Hope this helped hope you get a good score on your assignment/test/quiz/homework

3 0

2 years ago

32 plus 20 using the distributive property

Darya [45]

Using the distributive property it would be 4(8+5) which is the same as (4×8) + (4×5)

3 0

3 years ago

What is 154 x 3,975 and what is 197 x908

pochemuha

The answer for the first is 612,150. The answer for the second is 178,806.

3 0

2 years ago

Read 2 more answers

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

Find the values of a, b, and c from the quadratic equation
Substitute these values in the quadratic formula
Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

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9 0

2 years ago

Read 2 more answers