For which equation is x=0 NOT a solution?

1 answer:

4 0

B, is the only solution where x=0 isn’t the answer because 2.5x+3=x and if u subtract the 2.5x you get 3= -1.5x and if you divide 3 by -1.5 it won’t be x=0

You might be interested in

HELP ASAP I WILL MARK YOU BRAINLYEST PLEASE HURRY!!!!

Sidana [21]

X = 180 - 60 - 80
x = 40

hope it helps

3 0

3 years ago

Read 2 more answers

Approximate 47.96 to the nearest tenth

Iteru [2.4K]

Answer:

48.0

Step-by-step explanation:

8 0

3 years ago

What are the real zeros of x3 + 4x2 − 9x − 36?

ruslelena [56]

Answer:

Step-by-step explanation:

x^3+4x^2-9x-36=0

or x²(x+4)-9(x+4)=0

or (x+4)(x²-9)=0

or (x+4)(x+3)(x-3)=0

x=-4,-3 or 3

8 0

4 years ago

Find the polynomial of minimum degree, with real coefficients, zeros at x=4±2⋅i and x=−8, and y-intercept at −480. Write your an

valkas [14]

Answer:

The polynomial of minimum degree is $p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480$ .

Step-by-step explanation:

According to the statement, we appreciate that polynomial pass through the following points:

(i) $(4 + 2\,i,0)$ , (ii) $(4 - 2\,i, 0)$ , (iii) $(-8, 0)$ , (iv) $(0, -480)$

From Algebra we know that any n-th grade polynomial can be constructed by knowing n+1 different points. Hence, the polynomial of minimum degree is a quartic function. The polynomial has the following form:

$p(x) = (x-4-2\,i)\cdot (x-4+2\,i)\cdot (x+8)\cdot (x-r_{1})$