Given the propane molecule C3H8(g)! a) What is the balanced equation for the combustion of propane in O2?(20 pts.) b) What is th
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Answer:
a) the diffusion length = 1000 micrometers;
so if the diffusion co-efficient is also known or given; we can therefore deduce the time taken( i.e how long it would take for a message to reach from one side of the cell to the other).
b) We need to be given the data value concerning the diffusion coefficient of the protein.
c) 1.234 × 10⁷ seconds
Explanation:
a)
In a controlled transportation that occurs in diffusion; the time taken can be expressed as:
Now; if a message is passed through a ion, From studies; we know that these
ions are infinitesimally smaller in size in the
channels.
Also the information being carried through the ions are bound to be transported diagonally across the cell.
However; the diffusion length = 1000 micrometers;
so if the diffusion co-efficient is also known or given; we can therefore deduce the time taken( i.e how long it would take for a message to reach from one side of the cell to the other).
b) Since; we don't know the information concerning the diffusion coefficient of the protein, then it is quite not possible to determine how long it would take for a message to be transmitted through the diffusion of a small protein.
c) Here; we are given the value of the diffusion coefficient to be = 0.2 micrometer²/seconds
In a transmembrane protein; the diffusion length is half the circumference of the cell which is =
=
= 1570.8 micrometers
Now;the time taken can now be calculated as:
Answer:
La constante de equilibrio Ka del ácido láctico es 1.38x10⁻⁴.
Explanation:
El ácido láctico es un ácido débil cuya reacción de disociación es la siguiente:
CH₃CHOHCOOH + H₂O ⇄ CH₃CHOHCOO⁻ + H₃O⁺ (1)
0.025M - x x x
La constante de acidez del ácido es:
Sabemos que la concentración del ácido inicial es:
[CH₃CHOHCOOH] = 0.025 M
Y que a partir del pH podemos hallar [H₃O⁺]:
Debido a que el ácido se disocia en agua para producir los iones CH₃CHOHCOO⁻ y H₃O⁺ de igual manera (según la reacción (1)), tenemos:
[CH₃CHOHCOO⁻] = [H₃O⁺] = 1.78x10⁻³ M
Y por esa misma disociación, la concentración del ácido en el equilibrio es:
Entonces, la constante de equilibrio Ka del ácido láctico es:
Espero que te sea de utilidad!