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ira [324]
3 years ago
6

For each item: classify organic or inorganic.

Chemistry
2 answers:
Sloan [31]3 years ago
6 0

Answer 1) : NaCl - Sodium chloride is an inorganic salt.

Explanation : There is no carbon present in this molecule so, it can be referred as inorganic substance. Sodium Chloride contain Sodium and Chloride ions, the absence of carbon atom in the molecule makes this substance inorganic.

Answer 2) Phenol C_{6}H_{6}O - Phenol is an organic moiety.

Explanation : The presence of carbon bonded with hydrogen and oxygen makes the phenol compound as organic substance. Carbon here is present in large amount and imparts the organic character in phenol.

Answer 3) C_{2}H_{6} - Ethane is an organic compound.

Explanation : Ethane is an organic compound which contains carbon in its molecule and is covalently bonded with hydrogens present in the molecule. The presence of carbon makes the molecule as organic substance.

Answer 4) Ca_{3}(PO_{4})_{2} - Inorganic compound.

Explanation : Calcium phosphate is an inorganic compound which does not contains carbon atom in its molecule. The absence of carbon atom makes the compound inorganic. This calcium phosphate molecule only contains the molecules of calcium and phosphate in it.

Answer 5) Formaldehyde CH_{2}O - It is an organic compound.]

Explanation : Formaldehyde contains one molecule of carbon and two molecules of hydrogen along with one molecule of oxygen in it. The presence of carbon covalently bonded with hydrogen and oxygen makes it as an organic compound.

Answer 6) MgCO_{3} - Magnesium carbonate is an inorganic compound.

Explanation : Magnesium carbonate is inorganic substance as it does not contains carbon in its molecule. It only contains the molecules of magnesium and carbonate in it, which qualifies it to be called as inorganic compound.

Answer 7) Vitamin D_{2} (C_{27}H_{40}O) - It is organic compound.

Explanation : Vitamin D_{2} (C_{27}H_{40}O) it contains 27 molecules of carbon atoms which are covalently bonded with 40 molecules of hydrogen and a molecule of oxygen in its structure. Therefore, it can be called as organic.

Answer 8) Mercury Sulfate HgS - Inorganic compound.

Explanation : Mercury sulfate does not contains carbon in its molecular structure, which makes it as inorganic compound. It only contains the molecules of mercury and sulfate ions.

Answer 9) Butane C_{4}H_{10} - Organic compound.

Explanation : Butane contains 4 molecules of carbon which is covalently bonded with 10 molecules of hydrogen. The presence of carbon in its molecular structure makes butane as an organic compound.

Answer 10) Sand SiO_{2} - Inorganic compound.

Explanation : Sand which has the molecular formula as SiO_{2} does not contains carbon atom in its molecule. It just contains the molecules of silicon and two molecules of oxygen in it.

Answer 11) Water H_{2}O - It is an inorganic compound.

Explanation : Water molecule does not contains carbon in its molecule therefore, it is an inorganic compound. It contains only two molecules of hydrogen and one molecule of oxygen in it.

Scorpion4ik [409]3 years ago
6 0
<span>Clue: organic products have carbon and hydrogen bonded, and may contain othter elements, like O, F, Cl, Br, P, N, among other. C-H bonds

El H2CO3 es una excepción y es inorgánico.

1. NaCl: inorgánico (no tiene C)

2. phenol (C6H6O): .orgánico

3. C2H6: .orgánico

4. Ca3(PO4)2: .inorgánico (no tiene C y proviene de dos ácidos inorgánicos)

5. formaldehyde (CH20): .orgánico

6. MgCO3: .inorgánico (proviene el H2CO3, que ya dijimos que es ingorgánico)

7. vitamin D2 (C27H40O): .orgánico

8. mercury sulfate (HgS): .inorgánico (no contiene C)

9. butane (C4H10): .orgánico

10. sand (SiO2): .inorgánico (no contiene C)

11. water (H2O): </span>inorgánico (no contiene C)
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3 years ago
Ethanol melts at -114 degree C. The enthalpy of fusion
Brut [27]

Answer: The heat required is 6.88 kJ.

Explanation:

The conversions involved in this process are :

(1):ethanol(s)(-135^0C)\rightarrow ethanol(s)(-114^0C)\\\\(2):ethanol(s)(-114^0C)\rightarrow ethanol(l)(-114^0C)\\\\(3):ethanol(l)(-114^0C)\rightarrow ethanol(l)(-50^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of ethanol = 25.0 g

c_{p,s} = specific heat of solid ethanol= 0.97 J/gK

c_{p,l} = specific heat of liquid ethanol = 2.31 J/gK

n = number of moles of ethanol = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}}=\frac{25.0g}{46g/mole}=0.543mole

\Delta H_{fusion} = enthalpy change for fusion = 5.02 KJ/mole = 5020 J/mole

T_{final}-T_{initial}=\Delta T = change in temperature

The value of change in temperature always same in Kelvin and degree Celsius.

Now put all the given values in the above expression, we get

\Delta H=[25.0 g\times 0.97J/gK\times (-114-(-135)K]+0.534mole\times 5020J/mole+[25.0g\times 2.31J/gK\times (-50-(-114))K]

\Delta H=6885.93J=6.88kJ     (1 KJ = 1000 J)

Therefore, the heat required is 6.88 kJ

3 0
3 years ago
What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane
Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂  ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

  • 2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3  moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of  potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0
3 years ago
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