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alexira [117]
3 years ago
12

How much heat energy in joules is needed to raise the temperature of 500.0 g of water from 10.0°C to 63.5°C

Chemistry
1 answer:
wariber [46]3 years ago
8 0

Answer:

27692.5J

Explanation:

You might be interested in
Is potassium fluoride a covalent bond or ionic bond
Ivahew [28]

It's an ionic bond! Potassium is a cation, or a metal with a positive charge, and fluoride is an anion, or a nonmetal with a negative charge.

A covalent bond is the bond between two nonmetals.

Hope this helped!

7 0
3 years ago
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Has encontrado problemas de eutrofización en Xochimilco. Los habitantes del lugar te preguntan cuál es el problema y les dices q
Musya8 [376]

Answer: I go search some information

Explanation:I come back with a answer

3 0
3 years ago
Complete the following single replacement reaction. If they don’t react, just write “NR”
stiv31 [10]

We have to complete all the given reactions.

1. Fe(s) + CuCl₂ → Cu + FeCl₂

2. Cu(s) + FeCl₂(aq)  → NR (no reaction takes place)

3. K(s) + NiBr2(aq) → NR (no reaction takes place)

4. Ni(s) + KBr(aq) → K + NiBr₂

5. Zn(s) + Ca(NO₃)₂(aq) → NR (no reaction)

6. Ca(s) + Zn(NO₃)₂(aq) → Zn(s) + Ca(NO₃)₂(aq)

4 0
3 years ago
PLEASE HELP!!!!!!
pogonyaev

Answer:

m_{B}^{theoretical}=0.365gB

Y=87.1\%

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\   m_{B}^{theoretical}=0.365gB

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%

Best regards!

4 0
2 years ago
Here is a more complex redox reaction involving the dichromate ion in acidic solution: 3N O 2 − + 8H + + C r 2 O 7 2− → 3N O 3 −
Fantom [35]

Answer:

NO2- is the reducing agent.

Cr2O7_2- is the oxidizing agent.

H+ is neither

Explanation:

Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.

Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.

Let us look at the species.

The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.

Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.

Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.

The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.

4 0
3 years ago
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