Answer:
25.0 mol O₂ are required in the second reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6 H₂O(l)
Molar ratio in first reaction is 1:2
For every mol of N₂. I make 2 moles of ammonia. If I have 20 moles of N₂, i'm going to get, 40 moles of ammonia.
In the second reaction, molar ratio between products is 4:5.
If I obtained 40 moles of ammonia in first step, let's prepare the rule of three.
4 moles of ammonia react with 5 moles of O₂
40 moles of ammonia react with ( 40.5) /4 = 25moles
Answer:
0.0011 M.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of KMnO₄ = 0.0908 g
and ,
V = 0.500 L
Since ,
we know ,
m = Molecular mass of KMnO₄ = 158 g/mol
using , the above formula to calculate the moles ,
n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol
now , calculating the molarity as ,
M = n / V = 0.00057 mol / 0.500 L = 0.0011 M.
