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natali 33 [55]
2 years ago
11

Find the zeros of polynomial function and solve polynomials equations. f(x)=24x^3-64x^2-21x+56

Mathematics
1 answer:
8090 [49]2 years ago
8 0

Since this polynomial has 4 terms, factoring by grouping should be the first thing we try here.

So, we have:

8x^2(3x-8)-7(3x-8)=0 \implies\\ (8x^2-7)(3x-8)=0

So, we can use ZPP to find out roots:

3x-8 =0 \implies\\ x=\frac{8}{3}\\ 8x^2-7=0 \implies \\ 8x^2=7 \implies \\ x^2=\frac{7}{8} \implies \\ x=\pm\frac{\sqrt{7}}{\sqrt{{8}}}\\ \text{Rationalizing denominator:}\\ x=\pm\frac{\sqrt{56}}{8}

So our three roots are:

x \in \{\frac{8}{3},\frac{\sqrt{56}}{8},-\frac{\sqrt{56}}{8}\}

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Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
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2 years ago
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RideAnS [48]
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If m∠UNR = 180° find m∠RNS<br> A. 27°<br> B. 34°<br> C. 59°<br> D. 94°
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Answer:

Option A) m∠RNS=27°

Step-by-step explanation:

We know that m∠UNR = 180°. This tells us that the Sum of the enclosed angles should equal 180°, by trigonometry. So the enclosed angles are:

m∠RNS = (3x+6)^{o}

m∠SNT= (13x+3)^{o}

m∠TNU= (10x-11)^{o}

Now let us add all the angles and solve for the value of x as follow:

m_{RSN}+m_{SNT}+m_{TNU}=m_{UNR}\\\\(3x+6)+(13x+3)+(10x-11)=180\\\\3x+13x+10x+6+3-11=180\\\\26x-2=180\\\\26x=180+2\\\\26x=182\\\\

x=\frac{182}{26} \\\\x=7

Now lets plug in the value into the expression for angle m∠RNS to find the angle as:

RNS = (3x+6)^{o}\\\\RNS=(3(7)+6)^{o}\\\\RNS=(21+6)^{o}\\\\RNS=27^{o}

Thus Option A. is the correct answer.

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Step-by-step explanation:

I just took this geometry test with the same question. Its 15

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