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Hatshy [7]
4 years ago
14

Not sure need help ​

Mathematics
2 answers:
Veronika [31]4 years ago
8 0

Answer:

0.2 repeating is written as a fraction as 2/9

GrogVix [38]4 years ago
3 0
I’m sure it is 2/9... hope this helps ... if not then it’s 2 and a bar notation about the 2 over 10
You might be interested in
The area of a rectangle is 99in. The length of the rectangle is 2 in. Longer than the width. What is the width of the rectangle?
never [62]

(2+w)w=99

2w+w^2=99

w^2+2w-99=0

(w-9)(w+11)=0

W=9    w=-11

5 0
4 years ago
In ΔMNO, the measure of ∠O=90°, the measure of ∠M=66°, and NO = 60 feet. Find the length of MN to the nearest tenth of a foot.
nikklg [1K]

Answer: 65.7

Step-by-step explanation:

sinM=

hypotenuse

opposite

​

=

x

60

​

sin

⁡

66

=

60

x

sin66=

x

60

​

x

sin

⁡

66

=

60

xsin66=60

x

sin

⁡

66

sin

⁡

66

=

60

sin

⁡

66

sin66

xsin66

​

=

sin66

60

​

x

=

60

sin

⁡

66

=

65.6782

≈

65.7

feet

x=

sin66

60

​

=65.6782≈65.7 feet

3 0
3 years ago
Read 2 more answers
To get an estimate of consumer spending over a holiday season in 2009, 436 randomly sampled American adults were surveyed. Their
Tatiana [17]

Answer:

<em>-A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

<em>-This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

<em>-The margin of error is $4.4.</em>

<em>-This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

<em>-We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

<em />

Step-by-step explanation:

<em>A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

TRUE. The 90% confidence is less strict in its probability of having the mean within the interval, so it is narrower than the 95% CI. It relies more in the information given by the sample.

<em />

<em>In order to decrease the margin of error of a 95% confidence interval to a third of what is is now, we would need to use a sample 3 times larger. </em>

FALSE. The margin of error is z*σ/(n^0.5). So to reduce it by two thirds, the sample size n needs to be 3^2=9 times larger.

<em>This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

FALSE. There is no information about the skewness in the sample.

<em>The margin of error is $4.4.</em>

TRUE. The margin of error is (89.11-80.31)/2=$4.4.

<em>We are 95% confident that the average spending of these 435 American adults over this holiday season is between $80.31 and $89.11.</em>

FALSE. The CI is related to the populations mean. We are 95% confident that the average spending of the population is between $80.31 and $89.11.

<em>This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

TRUE. This happens accordingly to the Central Limit Theorem.

<em>95% of random samples have a sample mean between $80.31 and $89.11.</em>

FALSE. The confidence interval refers to the population mean.

<em>We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

TRUE. This is the conclusion that is looked for when constructing a confidence interval.

6 0
4 years ago
Bonnie and Allison went out to lunch. Their bill came to $15.00. If the girls left a 15% tip, how much did they pay for the meal
Luda [366]

Answer:

17.25

Step-by-step explanation:

15 * 15% = 2.25

2.25 + 15 = 17.25

5 0
3 years ago
A rectangle has side lengths of 1 3/4 feet and 2 1/3 feet. Find the perimeter of the rectangle. Write your answer as a mixed num
Sophie [7]

Answer:49/6ft

Step-by-step explanation:

3 0
3 years ago
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