Question

PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE

Answer 1

Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

Answer 2

Answer:

$\sf 0.192\:ms^{-2}\:\:(3\:s.f.)$

Explanation:

Given:

• initial velocity (u) = 50.0 km/h
• final velocity (v) = 36.5 km/h
• time (t) = 19.6 seconds

First, convert the velocities into meters per second by dividing by 3.6:

$\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}$

$\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}$

To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:

$\implies \sf v=u+at$

$\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a$

$\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a$

$\implies \sf 19.5a=-3.75$

$\implies \sf a=-\dfrac{3.75}{19.5}$

$\implies \sf a=-0.1923076923...\:ms^{-2}$

Therefore, the magnitude of acceleration is:

$\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)$

Learn more about Constant Acceleration Equations here:

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