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2 years ago

PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE

Physics

2 answers:

UkoKoshka [18]2 years ago

5 0

Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

frozen [14]2 years ago

3 0

Answer:

$\sf 0.192\:ms^{-2}\:\:(3\:s.f.)$

Explanation:

Given:

initial velocity (u) = 50.0 km/h
final velocity (v) = 36.5 km/h
time (t) = 19.6 seconds

First, <u>convert</u> the velocities into meters per second by dividing by 3.6:

$\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}$

$\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}$

To find the vehicle's <u>acceleration</u>, use one of the constant acceleration equations with the given values:

$\implies \sf v=u+at$

$\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a$

$\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a$

$\implies \sf 19.5a=-3.75$

$\implies \sf a=-\dfrac{3.75}{19.5}$

$\implies \sf a=-0.1923076923...\:ms^{-2}$

Therefore, the magnitude of acceleration is:

$\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)$

Learn more about Constant Acceleration Equations here:

brainly.com/question/27976125

brainly.com/question/26241670

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