All categories

2 years ago

PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE

Physics

2 answers:

UkoKoshka [18]2 years ago

5 0

Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

frozen [14]2 years ago

3 0

Answer:

$\sf 0.192\:ms^{-2}\:\:(3\:s.f.)$

Explanation:

Given:

initial velocity (u) = 50.0 km/h
final velocity (v) = 36.5 km/h
time (t) = 19.6 seconds

First, <u>convert</u> the velocities into meters per second by dividing by 3.6:

$\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}$

$\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}$

To find the vehicle's <u>acceleration</u>, use one of the constant acceleration equations with the given values:

$\implies \sf v=u+at$

$\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a$

$\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a$

$\implies \sf 19.5a=-3.75$

$\implies \sf a=-\dfrac{3.75}{19.5}$

$\implies \sf a=-0.1923076923...\:ms^{-2}$

Therefore, the magnitude of acceleration is:

$\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)$

Learn more about Constant Acceleration Equations here:

brainly.com/question/27976125

brainly.com/question/26241670

You might be interested in

Hey if your answering this can you just answer the number 14 I already got the rest<br> thanks

Scrat [10]

Layer a is the answer

7 0

3 years ago

Read 2 more answers

Which is an example of current electricity

Reil [10]

Answer:

A or B you choose

Explanation:

This is called current electricity or an electric current. A lightning bolt is one example of an electric current, although it does not last very long. Electric currents are also involved in powering all the electrical appliances that you use, from washing machines to flashlights and from telephones to MP3 players.

what is an electrical current, amp, ampere Current is the flow of electrons. When a circuit is closed then a current of electrons can flow and when a circuit is open then no current can flow. We can measure the flow of electrons just like you can measure the flow of water through a pipe.

4 0

2 years ago

Read 2 more answers

What can always be said about a negatively-charged ion?

KiRa [710]

Answer: A negatively-charged ion always has more electrons than protons

Explanation:

First, we know that the elementary negative charge is the electron, while the positive one is the proton. Such that both have the same charge in magnitude, but a different sign. Such that if we have the same number of electrons and protons in an atom, the charge of this atom will be neutral.

And an ion is an atom with a different number of electrons and protons, so the charge of the atom is not neutral.

Then if we have a negatively-charged ion, the charge of this atom is negative. Then we must have a larger number of electrons (the negative ones) than protons (the positive ones)

Then the correct option is:

A negatively-charged ion always has more electrons than protons

5 0

3 years ago

A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t

Mumz [18]

Answer:

$v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

$y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t$

Second stone:

$y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$

6 0

3 years ago

Read 2 more answers

The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equa

vlabodo [156]

The average amount of solar energy incident on the PV per day is 10000 kWh/day.

<h3>Equation</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let the PV array has an area equal to 50 square meters. Hence:

Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.

Find out more on Equation at: brainly.com/question/2972832

5 0

2 years ago