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loris [4]
2 years ago
12

PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE

Physics
2 answers:
UkoKoshka [18]2 years ago
5 0

Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

frozen [14]2 years ago
3 0

Answer:

\sf 0.192\:ms^{-2}\:\:(3\:s.f.)

Explanation:

Given:

  • initial velocity (u) = 50.0 km/h
  • final velocity (v) = 36.5 km/h
  • time (t) = 19.6 seconds

First, <u>convert</u> the velocities into meters per second by dividing by 3.6:

\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}

\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}

To find the vehicle's <u>acceleration</u>, use one of the constant acceleration equations with the given values:

\implies \sf v=u+at

\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a

\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a

\implies \sf 19.5a=-3.75

\implies \sf a=-\dfrac{3.75}{19.5}

\implies \sf a=-0.1923076923...\:ms^{-2}

Therefore, the magnitude of acceleration is:

\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)

Learn more about Constant Acceleration Equations here:

brainly.com/question/27976125

brainly.com/question/26241670

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Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
3 years ago
the two forces f1 and f2 acting at A have a resultant force of Fr= -100lb. determine the magnitude and coordinate direction angl
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Two forces F<span>1 and </span>F<span>2 act on the screw eye. The resultant force </span>FR<span> has a magnitude of 125 lb and the coordinate direction angles shown in (Figure 1) . Determine the magnitude of </span>F<span>2. Determine the coordinate direction angle </span>α<span>2 of </span>F<span>2. Determine the coordinate direction angle </span>β<span>2 of </span>F<span>2. Determine the coordinate direction angle </span>γ<span>2 of </span>F<span>2.</span>
8 0
2 years ago
Kyra and Pari are timing how long it takes for 1 g of sugar to dissolve in hot water. Kyra records a time of 24.3 seconds. Pari
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<h3>Answer:</h3><h3>we can say that:-</h3>
  1. A reading with more no of significant figures is considered to be more precise.
  2. Kyra recorded a reading of 24.3 sec. Since all non 0 digits are considered to be significant this reading has 3 significant figures.
  3. Pari recorded a reading of 24 sec. Since all non 0 digits are considered to be significant this reading has 3 significant figures.
<h3>hence we can say that kyra's reading has more significant figures nd so it is more precise.</h3>

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Explanation:

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=======================

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