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lara [203]
2 years ago
6

How fast must a 70 kg student be running to have a kinetic energy of 568 J?!

Physics
1 answer:
Dmitry [639]2 years ago
4 0

Answer: 4.03 m/s

Explanation: Kinetic energy is

KE = 1/2 m v²

So we derive the equation to have v.

v = √ 2KE / m

= 2 x 568 J / 70 kg

= 16.23

= √ 16.23

= 4.03 m/s

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Explanation:

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