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3 years ago

10 PTS! What type of lens is used to correct hyperopia? Explain your answer.

1 answer:

8 0

Hey there Cupcake589,
Concave lenses are used to correct hyperopia. They spread the light out before it reaches the convex lens in the eye, enabling the light from reaching the retina. Thus, allowing them to see clearly

Hope this helps :))

~Top♥

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A body has a velocity of 143 km/hr. Find its value in m/s.

kozerog [31]

39.72 m/s is the velocity of the body.

3 0

4 years ago

A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one

user100 [1]

Answer:

The value is $k = 51.34 \ N/ m$

Explanation:

From the question we are told that

The mass is $m = 1.3 \ kg$

The needed oscillation time is $T = 1 \ s$

Generally the spring constant is mathematically represented as

$k = \frac{4 \pi^2 * m }{ T^2}$

=> $k = \frac{4* 3.142^2 * 1.3 }{ 1^2}$

=> $k = 51.34 \ N/ m$

5 0

3 years ago

Viewed at night from the high diving board at a swimming pool, the light from an underwater bulb forms a bright, 10-ft diameter

ycow [4]

Answer:

option A

Explanation:

given,

diameter of circle = 10 ft

refractive index of the water = n = 1.33

let the inclined surface of the cone makes an angle θ with vertical line then

$tan \theta = \dfrac{radius\ of\ circle}{verticle\ length}$

$h= \dfrac{radius}{tan\theta }$

we know,

$sin \theta = \dfrac{1}{n}$

$sin \theta = \dfrac{1}{1.33}$

$\theta =sin^{-1}(\dfrac{1}{1.33})$

from this θ = 48.75°

substitute this in eq ( 1 ) we have

$h= \dfrac{5}{tan 48.75}$

h = 4.38

h = 4.4 (approx.)

Hence, the correct answer is option A

3 0

3 years ago

Sound of thunder is heard 5 seconds after the flash of lightning is seen.How far away was the lightning flash? Note that sound t

elena55 [62]

Answer:

The distance covered by the lighting flash is 1700 meters.

Explanation:

Given that,

The speed of sound travels in air at a speed of about 340 meter second, v = 340 m/s

The sound of thunder is heard 5 seconds after the flash of lightning is seen, t = 5 s

To find,

The distance far away was the lightning flash.

Solution,

The distance covered by the lighting flash is given by the product of speed and time. It is given by :

$d=v\times t$

$d=340\ m/s\times 5\ s$

d = 1700 meters

So, the distance covered by the lighting flash is 1700 meters. Therefore, this is the required solution.

3 0

4 years ago

What would be the kinetic energy k2q of charge 2q at a very large distance from the other charges? express your answer in terms

Pavlova-9 [17]

Answer:

$K_{2q}=\frac{7.76kq^2}{d}$

Explanation:

At the corner of the square, the potential energy of interaction of other charges with the charge 2q is given by $U_{2q}$

$U_{2q,i}=k\frac{(2q)(q)}{d}+k\frac{(2q)(5q)}{d}+k\frac{(2q)(-3q)}{\sqrt{2}d}=\frac{7.76 kq^2}{d}$

Also, since $K_{2q,i}=0$

The initial energy of the system is given by;

$E_i=U_{2q ,i}+K_{2q,i}=\frac{7.76kq^2}{d}+0=\frac{7.76kq^2}{d}$

Since $U_{2q,f}=0$

, the final energy of the system is obtained by

$E_f=U_{2q ,f}+K_{2q,f}=0+K_{2q,f}$

From the law of conservation of energy, $E_i=E_f$

Therefore, $K_{2q}=\frac{7.76kq^2}{d}$

7 0

3 years ago