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MAXImum [283]
3 years ago
9

Which term describes the difference in electrical charge across a membrane? View Available Hint(s) Which term describes the diff

erence in electrical charge across a membrane? Resting potential. Membrane potential. Electrical current. Electrical potential. Submit
Physics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

Membrane potential

Explanation:

Membrane potential is describes the difference in electrical charge across a membrane.                                                                                                              

The difference in potential between exterior  and  interior of the  biological cell is known as Membrane potential.Generally it is denoted by  millivolts like mV and varies from -80 V to -40 V.

So the answer is Membrane potential

You might be interested in
As a mass on a spring moves farther from the equilibrium position, how do the velocity, acceleration, and force change
Umnica [9.8K]
Refer to the diagram shown below.

m =  the mass of the object
x = the distance of the object from the equilibrium position at time t.
v = the velocity of the object at time t
a = the acceleration of the object at time t
A =  the amplitude ( the maximum distance) of the mass from the equilibrium
        position

The oscillatory motion of the object (without damping) is given by
x(t) = A sin(ωt)
where
ω =  the circular frequency of the motion
T =  the period of the motion so that ω = (2π)/T

The velocity and acceleration are respectively
v(t) = ωA cos(ωt)
a(t) = -ω²A sin(ωt)

In the equilibrium position,
x is zero;
v is maximum;
a is zero.

At the farthest distance (A) from the equilibrium position,
x is maximum;
v is zero;
a is zero.

In the graphs shown, it is assumed (for illustrative purposes) that
A = 1 and T = 1.

6 0
3 years ago
Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio
leva [86]

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

5 0
3 years ago
Read 2 more answers
A measurement must include both a number and a(an)
IrinaK [193]
<span>A measurement must include both a number and an unit of measurement. </span>
7 0
3 years ago
A ray of light incident in water strikes the surface separating water from air making an angle of 10 ° with the normal to the su
labwork [276]

Answer:

a

 \theta _2  = 13^o

b

 \theta _1  =32.94^o

c

 \theta_c  =  53.05^o    

Explanation:

From the question we are told that

    The angle of incidence is  \theta_1 =  10^o

    The refractive index of water is  n_1 = 1.3

  Generally Snell's law is mathematically represented as

          n_1 sin(\theta_1) =  n_2 sin(\theta_ 2)

Here n_2 is the refractive index of air with value  n_2 =  1

         \theta_2  is the angle of refraction

So  

        \theta _2  =  sin^{-1}[\frac{n_1 * sin(\theta _1)}{n_2} ]

=>     \theta _2  =  sin^{-1}[\frac{1.3 * sin(10)}{1} ]

=>     \theta _2  = 13^o

Given that the angle should not be greater than \theta _2 =45^o  then the angle of incidence will be

       \theta _1  =  sin^{-1}[\frac{n_2 * sin(\theta _2)}{n_1} ]

=>     \theta _1  =  sin^{-1}[\frac{1 * sin(45)}{1.3} ]

=>     \theta _1  =32.94^o

Generally for critical angle is mathematically represented as

        \theta_c  =  sin^{-1}[\frac{n_2}{n_1} ]

=>     \theta_c  =  sin^{-1}[\frac{1}{1.3} ]  

=>     \theta_c  =  53.05^o            

4 0
2 years ago
Two small identical metal spheres, A and B, on insulated stands, are each given a charge of +2.0 x 10-5 coulomb. The distance be
SpyIntel [72]

Answer:

a) 90 N

Explanation:

Coulomb's law: states that the electric force of attraction or repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

It is represented mathematically as

F = 1/4πε₀(q₁q₂)/d²......................... Equation 1

Where F = Electrostatic force, q₁ = charge on the first metal sphere, q₂ = charge on the second metal sphere, d = distance between the spheres, 1/4πε₀ = proportionality constant.

<em>Given: q₁ = +2.0×10⁻⁵ C, q₂ = 2.0×10⁻⁵, d = 2.0×10⁻¹ m</em>

<em>Constant : 1/4πε₀ = 9×10⁹Nm²/C²</em>

<em>Substituting these values into equation 1,</em>

<em>F = (9×10⁹×2.0×10⁻⁵×2.0×10⁻⁵)/(2.0×10⁻¹)²</em>

<em>F = (9×4×10⁻¹)/4×10⁻²</em>

<em>F = 90 N</em>

Therefore the electrostatic force is = 90 N

The right option is a) 90 N

5 0
2 years ago
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