You have $55 and spend x dollars. How much money do you have left?

PLEASE HELP ME.<br><br> Is the point (3,-2) on the graph of 3x – 2y = 12?

Zinaida [17]

Answer:

use photo math, take a picture of the equation, go down to the graph and see if there is a plot on (3,-2)

3 0

2 years ago

Find the mean and median of the following data set:

VARVARA [1.3K]

Answer:

Mean: 23. 54545455

Median: 22

Step-by-step explanation:

The median represents the center the most because when you are solving for the median, you look for the direct center of the terms which will be 22, the median.

6 0

2 years ago

If the area of a right-angled triangle is 47 56 cm and its height is 11.6 cm. finds its base.

Wewaii [24]

Answer:

820

Step-by-step explanation:

Hi so if your area is 4756, the base would be 820

8 0

2 years ago

write an equation in slop-intercept form for a line that is perpendicular to the line y= -5x-3 and has a y-intercept of 6.

jenyasd209 [6]

Answer:

The equation of the line would be y = 1/5x + 6

Step-by-step explanation:

First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is -5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.

Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.

y = mx + b

y = 1/5x + 6

6 0

2 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574$

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0

2 years ago