One possible strategy would be to find the cane toads natural predators. if the cane toad does have natural predators, then it can control the population by hunting it and etc. one limitation to this however would be that there has to be an balance between the toad and that natural predator. for example, they need to survive off of each other so there can’t be too many of the toads not so many natural predators and vise verse. (i hope this makes sense i took bio last year)
Answer:
A gene codes for a particular protein that is involved in the expression of a trait.
Explanation:
Characteristics determined by single genes are called Mendelian traits.
Answer:
clustered distribution (clumped)
Explanation:
In ecology, species distribution refers to the way in which a biological taxon is spatially arranged in a particular geographic area. Species patterns of distribution are fundamental to analyze ecological systems. The main distribution patterns include 1-clustered (clumped) distribution, 2-uniformed distribution, and 3-randomized distribution. The clustered distribution is the most common type of dispersion pattern in nature and occurs when species tend to form small sets of three or more individuals clustered together. A clustered distribution may be due, for example, when resources (e.g., water) are not evenly distributed in the environment (unequal distribution of the resources). Moreover, a uniform distribution occurs organisms keep a uniform, constant, distance from each other (e.g., due to competition for limited resources), while a randomized distribution occurs when individuals are randomly distributed because resources are not limited.
Answer:
Approximately 12,500 SARS-CoV-2 viruses
Explanation:
According to this question, the period described is 1mm in diameter. Since 1millimetre(mm) is 1000metre(m), this means that the period is 0.001m in diameter.
Also, the SARS-CoV-2 virus has a diameter of 80 nm (1nm = 10^9m).
Since 10^6nanometres (nm) or 1,000,000nm makes 1millimeter (mm), 80nm of the virus will be:
= 80/1,000,000
= 0.000080mm or 8 × 10^-5mm
To calculate how many of the SARS-CoV-2 virus will fit into the period, we divide the diameter of the period (in mm) by the diameter of the virus (in mm).
That is; 1 ÷ 8 × 10^-5
= 1/8 × 10^5
= 0.125 × 100,000
= 12,500
Therefore, approximately 12500 SARS-CoV-2 viruses will fit in the period.