Answer:
<h2>measures the pressure of blood when the heart contracts and relaxes.. </h2>
Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Answer:
the last one house cats lions and tigers belong to the same class abd and family
Answer:
<em>The total amount of energy transferred during photosynthesis for this ecosystem equals</em><em> 260,000 kcal/m2/yr.</em>
Explanation:
To answer this question, we need to know that
- gross primary productivity (GPP) = energy captured and converted into chemical energy during photosynthesis
- net primary productivity (NPP) = difference between GPP and respiration rate
So, to calculate GPP we need to sum NPP to Respiration rate. This if,
NPP = 165,000 kcal/m2/yr
R = 95,000 kcal/m2/yr
NPP = GPP – Respiration
Then,
GPP = NPP + R
GPP = 165,000 kcal/m2/yr + 95,000 kcal/m2/yr
GPP = 260,000 kcal/m2/yr
Without wolves of course, because wolves eat deer :D
