Answer:
The water cycle consists of 3 major processes.
**Evaporation
**Condensation.
**Precipitation.
01)Evaporation, : Evaporation is the process of a liquid s surface changing into a gas.
02)Condensation: Condensation is the process of gas changing to a liquid.
03)Precipitation: In the water cycle, water vapour in the atmosphere condenses and become liquid.
WHAT IS WATER CYCLE DO?
## The water cycle shows the continues movement of water within the Earth and atmosphere.
** Liquid Water--------------- Water vapour. ( Evaporate)
*** Condenses-------- To Clouds
( Turn)
, and precipitations back to the form of rain and snow. Water do transform around the atmosphere.
Tip::: who made the water cycle???
The sun heat.
Sadanavam1979 Greetings
So, when two different air masses meet, a boundary is formed. The boundary between two air masses is called a front. Weather at a front is usually cloudy and stormy. There are four different fronts- Cold, Warm, Stationary, and Occluded.
Answer: This means to find the number of neutrons you subtract the number of protons from the mass number.
Answer : The concentration of HI (g) at equilibrium is, 0.643 M
Explanation :
The given chemical reaction is:
Initial conc. 0.10 0.10 0.50
At eqm. (0.10-x) (0.10-x) (0.50+2x)
As we are given:
The expression for equilibrium constant is:
![K_c=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
Now put all the given values in this expression, we get:
x = 0.0713 and x = 0.134
We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.
Thus, we are taking value of x = 0.0713
The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M
Thus, the concentration of HI (g) at equilibrium is, 0.643 M
Answer:
67.5 moles of O2
Explanation:
2 C
8
H
18 + 27
O
2 → 16
C
O
2 + 18
H
2
O
According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...
