Answer:At the molecular level, the pressure of a gas depends on the number of collisions its molecules have with the walls of the container. If the pressure on the piston is doubled, the volume of the gas decreases by one-half. The gas molecules, now confined in a smaller volume, collide with the walls of the container twice as often and their pressure once again equals that of the piston.
Explanation:
<span>C7H16 + 11O2 ------> 7CO2 + 8H2O
</span><span>C- 7 C- 7
H- 16 H -8*2=16
O -11*2 =22 O - 7*2 +8 =14+8=22</span>
