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scoray [572]
3 years ago
9

If you obtain 3.0 grams of aspirin from an experiment that could make no more than 3.14 grams, what is the percent yield?

Chemistry
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

96%

Explanation:

To find the percent yield, we can use this equation

\frac{Actual}{Theoretical} *100

The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.

\frac{3.0}{3.14} *100\\\\ =96

Thus the percent yield is 96%

;)

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What is the molar mass of a gas if 0.102 g of the gas occupies 0.070 L at STP? a. 32.6g / mol b. 28.2 g/mol c. 40.0g / mol d. 47
alexgriva [62]

Answer:

A. 32.6 g/mol

Explanation:

First convert the volume of gas to moles using the ratio 1 mol / 22.4 L at STP.

0.070 L • (1 mol / 22.4 L) = 0.00313 mol

Now divide the grams of gas by the moles of gas:

0.102 g / 0.00313 mol = 32.6 g/mol

8 0
3 years ago
In a mixture of 2 ideal gases, A and B, PA = 0.2PB, what is the mole fraction of A?
Alborosie

Answer:

0.1667

Explanation:

Hello,

Dalton's law defines:

y_i=\frac{P_i}{P_T}

A total pressure is:

P_T=P_A+P_B

So, for A (solving for P_A in the previous equation, we get:

y_A=\frac{P_A}{P_A+P_B}

Since P_A=0.2P_B, we obtain:

y_A=\frac{P_A}{P_A+P_A/0.2}\\y_A=\frac{1}{6}\\y_A=0.1667}

Best regards.

7 0
3 years ago
What charge would Balloon #2 have? How did you determine this?
tigry1 [53]

Answer:I belive it would be attracted seeing as how there are more magmatic charges on that side of no 2 and how there are more positive charges on the middle side of ballon no1.

Explanation:

4 0
3 years ago
To balance a half-reaction in basic solution, you need to add enough of which substances to balance the equation?
LenKa [72]
I'm not sure if this is what you're looking for, but I suppose you would have to have the solute and the solution to balance the reaction.
4 0
3 years ago
Read 2 more answers
Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by
alexdok [17]

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

ΔTb=Tb (solution) - Tb (pure solvent)

14.65=Tb (solution)-118.1

Tb (solution)=118.1+14.65

=132.75

3 0
3 years ago
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