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hichkok12 [17]
3 years ago
5

Multiplying a trinomial by a trinomial follows the same steps as multiplying a binomial by a trinomial. Determine the degree and

maximum possible number of terms for the product of these trinomials: (x2 + x + 2)(x2 – 2x + 3). Explain how you arrived at your answer.

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0
I think this attachment will help you

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Use the numbers 5,6, and 7 and the operations of addition,subtraction, multiplication, and/or division to create three different
mars1129 [50]

1. 5x6+7

2. 6x7+5

3. 5x7+6

Hope I helped :)


5 0
3 years ago
Read 2 more answers
Plz help me, URGENT!! 20 points!
Evgen [1.6K]

Answer:

The answer to your question is 37.5

4 0
3 years ago
-45*5x+3x=666<br><br> A) -2<br> B) -3<br> C) 2<br> D) 3
Ivahew [28]

Answer: -3

Step-by-step explanation: Explanation is below

:) Hopes this helps!

3 0
3 years ago
f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.
trasher [3.6K]

( x + (x  -  9))  \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88
x =  \frac{88}{4}  = 22
the length is 22


and the width is
22-9=17





good luck
3 0
3 years ago
If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)
lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

✌ ✌ ✌ ✌

3 0
2 years ago
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